Answer:
2.66 (rounded to the nearest hundredth)
Divide both sides by 4
e^(2.7x) = 8.25
Take natural logarithm of both sides
2.7x = ln 8.25
x = (ln 8.25)/2.7 = ln (8.25^(1/2.7))
The number of liver cells it would take to form an end to end chain 10 in long is 12,700 liver cells
<h3>Calculating quantity</h3>
From the question, we are to determine how many liver cells it would take to form an end to end chain 10 in long
First, we will convert 10 in to meters
1 inch = 0.0254
∴ 10 inches = 0.254 m
From the giving information,
A liver cell is about 20 μm in diameter
∴ The number of liver cells it would take to form an end to end chain 10 in long = 0.254 m / 20 μm
= 0.254 m / (20 ×10⁻⁶) m (NOTE: 1μm = 10⁻⁶m)
= 12700
Hence, the number of liver cells it would take to form an end to end chain 10 in long is 12,700 liver cells
Learn more on Calculating quantity here: brainly.com/question/2021001
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Answer:
y=mx+c, m represents the slope while c the y-intercept. (never forget that)
It only goes 8 times cause 3×9 = 27 and 3×8 = 24