Could you guys please help me with this :3

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

Find x <br> 3x+1=2x-2<br> show all work pls

spayn [35]

See attached photo:

8 0

3 years ago

Read 2 more answers

The square below represents a unit or a whole. What fraction is represented by the

Mkey [24]

20/28 or 10/14 or 5/7
You can keep reducing until both sides of the fraction can't be divided by the same number anymore.

5 0

2 years ago

A water skiing jump is 4.6m long. It rises 1.1m. What

lorasvet [3.4K]

The inclination to the nearest tenth of a degree exists 0.24146

<h3>What is the inclination to the nearest tenth of a degree?</h3>

The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.

Given: H = 4.6 m and P = 1.1 m

We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse

Let x be the angle then

sin x = P/H

sin x = 1.1/4.6

sin x = 0.23913

$$$sin^{-1} x$ = 0.24146

The inclination to the nearest tenth of a degree exists 0.24146

To learn more about trigonometric ratios refer to:

brainly.com/question/14033725

#SPJ9

4 0

11 months ago

Use the substitution method to solve the system of equations. Choose the correct ordered pair. x + y = 11 -x = -y - 9

suter [353]

$x+y=11 \\
-x=-y-9 \\ \\
\hbox{substitute the second equation by -1} \\ \\
x+y=11 \\
x=y+9 \\ \\
\hbox{substitute y+9 for x in the first equation} \\ \\
y+9+y=11 \\
2y=11-9 \\
2y=2 \\
y=\frac{2}{2} \\
y=1 \\ \\
x=y+9 \\
x=1+9 \\
x=10 \\ \\
(x,y)=(10,1)$

The answer is B.

5 0

2 years ago

Read 2 more answers