Answer:
Step-by-step explanation:
First we have to assume the smallest integer.
Let,
the smallest integer is x
So, the other two integers are-
x+1 and x+2
Now,
the sum of these 3 integers is greater than smallest integer by 11
So, we get
x+(x+1)+(x+2) =x+11
This is the required equation.
Answer:
a+4b-24
Step-by-step explanation:
(x-xo)²+(y-yo)²=r²
(x-9)²+(y-3)²=64
r²=64
Area of a circle=πr²=3.14×64=200.96
9514 1404 393
Answer:
nπ -π/6 . . . for any integer n
Step-by-step explanation:
tan(x) +√3 = -2tan(x) . . . . . given
3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3
tan(x) = -√3/3 . . . . . . . . . . divide by 3
x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x
This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...
x = n·π -π/6 . . . . for any integer n
