It does, it has a lot of resources that we can take advantage of. It depends on how you use it
Answer:
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Answer:C)Extranet
Explanation: Extranet is the network on private basis for sharing of the organizational information with the vendors, employees, customers,suppliers etc. It uses the internet service for the distribution of the data outside of the company in extended form.Electronic data interchange is used for exchanging of large amount of information.
Other options are incorrect because intranet is the internet service which works within enterprise, chaosnet is protocol for transmission of data in full duplex form and ethernet is the communication with the help of protocol in traditional manner.
Answer:
1 will be stored in result
Explanation:
Given
The lines of code
Required
Determine the value stored in result
The value stored in result is determine by the condition (x<3 && y ==6)
In the first line, the value of x is 2 and the value of y is 6
So: x<3 is true because x = 2 and 2 is less than 3
y == 6 is also true because y = 6 and 6 is equal to 6
So, the condition (x<3 && y ==6) is true and true will be saved in variable result
Because result is a Boolean variable which can only take true or false value
1 represents true
0 represents false
<em>So, 1 will be stored in result</em>
Answer:
In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.
Explanation:
We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).
Using First-fit
First-fit means you assign the first available memory that can fit a process to it.
- 115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).
- 500KB will fit into the second partition. So, F2 will have a remaining free space of 100KB (600 - 500)
- 358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)
- 200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)
- 375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)
Using Best-fit
Best-fit means you assign the best memory available that can fit a process to the process.
- 115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)
- 500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)
- 358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)
- 200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)
- 375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)
Using Worst-fit
Worst-fit means that you assign the largest available memory space to a process.
- 115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)
- 500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)
- 358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)
- 200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)
- 375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.
