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3 years ago

Which of the following is a narrative essay most like

Computers and Technology

2 answers:

lesya [120]3 years ago

6 0

I think it cut off? Doesn’t make any sense

JulijaS [17]3 years ago

5 0

A narrative uses “I” “me” and it is about a personal experience or event.. but there are no choices in this question so I did the best I could.

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Hdhdhrhdh you are not the intended recipient. xmp-qite-xsy.

Aleks04 [339]

Answer:

ummmm... okay

Explanation:

3 0

3 years ago

Suppose you can access the caches in the local DNS servers of your department. Can you propose a way to roughly determine the We

lubasha [3.4K]

Answer:

We can periodically take a snapshot of the Domain Name System (DNS) caches in the local Domain Name System (DNS) servers.

Explanation:

We can periodically take a snapshot of the Domain Name System (DNS) caches in the local Domain Name System (DNS) servers. The Web server that appears most frequently in the Domain Name System (DNS) caches is the most popular server. This is because if more users are interested in a Web server, then Domain Name System (DNS) requests for that server are more frequently sent by users. Thus, that Web server will appear in the Domain Name System (DNS) caches more frequently.

6 0

3 years ago

You often insert your company's logo into a document you create.one way to make it easier for you to quickly insert it is to sav

eduard

Save the logo as a TEMPLATE.

A template is a pre-developed page layout in soft copy or hard copy used to make pages with the same pattern, style, or design.

In the above scenario, you can prepare a template with you logo in it and save it for future use. In the event that you need to create a new document, you only have to bring up the saved template and edit it with the new information that you need to type.

This way, you will not be hassled to manually add your logo to every new document you create.

5 0

3 years ago

Write a program that lets the user enter the name of a team and then displays the number of times that team has won the World Se

xz_007 [3.2K]

Answer:

see explaination

Explanation:

import java.io.*;

import java.util.Scanner;

public class Winners {

public static void main(String args[]) throws IOException {

Scanner sc = new Scanner(new File("WorldSeriesWinners.txt"));

String commands[] = new String[100000];

int c = 0;

while (sc.hasNextLine()) {

String input = sc.nextLine();

System.out.println(input);

if (input.isEmpty())

continue;

commands[c++] = input;

}

sc.close();

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter the name of a team: ");

String name = keyboard.nextLine();

int count = 0;

for (int i = 0; i < c; i++) {

if (commands[i] != null) {

if (commands[i].equals(name)) {

++count;

}

if(count!=0)

System.out.println(name + " has won the World Series in the time period from 1903 through 2018 " +count + " number of times" );

else

System.out.println("Team with name "+name+ " does not exists");

}

5 0

3 years ago

Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r

kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

INVOKE Str_find,ADDR target, ADDR source

mov position,eax

jz wasfound ; ZF=1 indicates string found

mov edx,OFFSET str3 ; string not found

call WriteString

jmp quit

wasfound: ; display message

mov edx,OFFSET str1

call WriteString

mov eax,position ; write position value

call WriteDec

mov edx,OFFSET str2

call WriteString

quit:

exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

; to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

INVOKE Str_length,pTarget ; get length of target

mov lenTarget,eax

INVOKE Str_length,pSource ; get length of source

mov lenSource,eax

mov edi,OFFSET target ; point to target

mov esi,OFFSET source ; point to source

; Compute place in target to stop search

mov eax,edi ; stop = (offset target)

add eax,lenTarget ; + (length of target)

sub eax,lenSource ; - (length of source)

inc eax ; + 1

mov stop,eax ; save the stopping position

; Compare source string to current target

cld

mov ecx,lenSource ; length of source string

L1:

pushad

repe cmpsb ; compare all bytes

popad

je found ; if found, exit now

inc edi ; move to next target position

cmp edi,stop ; has EDI reached stop position?

jae notfound ; yes: exit

jmp L1 ; not: continue loop

notfound: ; string not found

or eax,1 ; ZF=0 indicates failure

jmp done

found: ; string found

mov eax,edi ; compute position in target of find

sub eax,pTarget

cmp eax,eax ; ZF=1 indicates success

done:

ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0

3 years ago