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AysviL [449]
3 years ago
8

Which of the following is a narrative essay most like

Computers and Technology
2 answers:
lesya [120]3 years ago
6 0
I think it cut off? Doesn’t make any sense
JulijaS [17]3 years ago
5 0
A narrative uses “I” “me” and it is about a personal experience or event.. but there are no choices in this question so I did the best I could.
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Write only in C, not C++.
yawa3891 [41]

Answer:

#include <iostream>

using namespace std;

int main() {

  int k;

double d;

string s;

cin >> k >> d >> s;

cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s; }

                                                                   

Explanation:

k is int type variable that stores integer values.

d is double type variable that stores real number.

s is string type variable that stores word.

cin statement is used to take input from user. cin takes an integer, a real number and a word from user. The user first enters an integer value, then a real number and then a small word as input.

cout statement is used to display the output on the screen. cout displays the value of k, d and s which entered by user.

First the values of k, d and s are displayed in reverse order. This means the word is displayed first, then the real number and then the integer separated again by EXACTLY one space from each other. " " used to represent a single space.

Then next line \n is used to produce a new line.

So in the next line values of k, d and s are displayed in original order (the integer , the real, and the word), separated again by EXACTLY one space from each other.

The program along with the output is attached.

7 0
3 years ago
*asap* Name one of the similarities between Word and Excel.
Yakvenalex [24]
The similarities are:  in both programs you can type letters, insert images, hyperlinks.
7 0
3 years ago
One of your start-ups uses error-correcting codes, which can recover the original message as long as at least 1000 packets are r
Marina CMI [18]

Answer:

Number of packets ≈ 5339

Explanation:

let

X = no of packets that is not erased.

P ( each packet getting erased ) = 0.8

P ( each packet not getting erased ) = 0.2

P ( X ≥ 1000 ) = 0.99

E(x) = n * 0.2

var ( x ) = n * 0.2 * 0.8

∴ Z = X - ( n * 0.2 ) / \sqrt{n*0.2*0.8}   ~ N ( 0.1 )

attached below is the remaining part of the solution

note : For the value of <em>n</em> take the positive number

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3 years ago
50 points please!!
MA_775_DIABLO [31]

Answer:

poopypoopypoopypoopy

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3 years ago
I do not understand what the are asking in csys 1.3.6
Amiraneli [1.4K]

Can i see the note????

6 0
2 years ago
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