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amid [387]
3 years ago
12

Tanya runs diagonally across a rectangular field that has a length of 40 yards and a width of 30 yards, as shown in the diagram.

What is the length of the diagonal, in yards, that Tanya runs?
Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:

70 besarse you have to add

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From 1960 to 1980, the consumer price index (CPI) increased from 34.6 to 82.4 If a gallon of milk cost $0.75 in 1960 and the pri
bonufazy [111]
Hello! So, we could set up a proportion to solve this, because the price and CPI increased at the same rate. Let's set it up like this: 34.6/82.4 = 0.75/x. This is because we know the prices from the 1960's, but we don't know the gallon of milk price in 1980, and we line them up like that to make sure we get the proper answer. Cross multiply the values in order to get 34.6x = 61.8. Now, divide each side by 34.6 to isolate the variable. x ≈ 1.7861 and other numbers behind it or 1.79 when rounded to the nearest hundredth. The price for a gallon of milk in 1980 was about $1.79.
8 0
4 years ago
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What is the solution to 2x-8<12?
max2010maxim [7]

Answer:

X=10

Step-by-step explanation:

2x-,8<12

2x>12+ 8

2x>20

x>10

6 0
3 years ago
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Hola chicos, solo necesito ayuda con la vida. Solo bromeaba o lo estoy?
creativ13 [48]

Answer:

no sé eres tú

Step-by-step explanation:

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3 years ago
3 2/4 pieces f cake after party eats 1 /2/3 next night how much does she have left
xz_007 [3.2K]
The person has 1 5/6 cake left because 3 2/4 - 1 2/3 = 1 5/6! Hope this helps ^0^

Explanation 
Rewriting Expression in different parts.
= 3 + 2/4 + 1 + 2/3.

Solving The Whole Number Parts.
3 + 1 = 4

Solving The Fraction Parts.
2/4 + 2/3 = ?

Find the LCD of 2/3 and 2/4 and Rewrite to solve with equivalent Fractions.
LCD = 12

6/12 + 8/12 = 14/12

Simplify the Fraction Part.
14/12 = 7/6

Simplify The Fraction Part Again.
7/6 = 1 1/6

Combining The Whole Numbers With The Fractions.
4 + 1 + 1/6 = 5 1/6 

Hope this helps ^0^! ;D
8 0
4 years ago
Please find question in photo below. I’m revising for a test I have in a few days, and I can’t figure this out. Please help!
Temka [501]

\large{\rm{\underline{\underline{Answer:}}}}

a) <u>n² + 6 </u>

~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.

  • If n = 1, first term = 1² + 6 = 7
  • n = 2, second term = 10
  • n = 3, third temm = 15
  • n = 4, fourth term = 22
  • n = 10, tenth term = 106

b) <u>3n²</u>

  • If n = 1, first term = 3
  • n = 2, second term = 12
  • n = 3, third term = 27
  • n = 4, fourth term = 48
  • n = 10, tenth term = 300
3 0
3 years ago
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