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ohaa [14]
2 years ago
6

A teacher tells her students she is just over 1 and billion seconds old.

Mathematics
2 answers:
-Dominant- [34]2 years ago
6 0

Step-by-step explanation:

Words Decimal Representation Scientific Notation

ten million 10,000,000 1 x 107

one hundred million 100,000,000 1 x 108

one billion 1,000,000,000 1 x 109

ten billion 10,000,000,000 1 x 1010

SOVA2 [1]2 years ago
4 0
1,000,000,000 1 x 109
One year = (365)x(24)x(60)x(60)
Seconds = 31,536,000 seconds= 31.536 million seconds
So 1 Billion Seconds
(1000,000,000)/31,536,000= 31.536 years
So 1 billion seconds would be 31 years 8 mouths 19 days 1 hour 46 minutes and 4 seconds
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Help me solve the binary operations please ​
son4ous [18]

Answer:

  • 3*2=\sf{\pink{\dfrac{4}{5}}}

Step-by-step explanation:

<u>Given</u><u> </u><u>that</u><u>,</u><u> </u>

x*y=\dfrac{(2x-y)}{(x+y}

<h3><u>SO</u><u>,</u><u> </u></h3>

3*2=

\dfrac{2(3)-2}{3+2}\\\\\dfrac{6-2}{5}\\\\\dfrac{4}{5}

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6 0
2 years ago
The left and right page numbers of an open book are two consecutive integers whose sum is 321
PIT_PIT [208]

Answer:

160,160

Step-by-step explanation:

let the first page be X

second one be x+1

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x= 320÷2=160

pages 160 161

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3 years ago
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PSYCHO15rus [73]
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7 0
3 years ago
Sam invests £1800 in the bank for four
KIM [24]

Answer:

£2088

or

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8 0
3 years ago
Use an induction proof to prove this statement:<br> For n≥1, 4^n+5 is divisible by 3.
Tpy6a [65]

Answer:

See below

Step-by-step explanation:

We shall prove that for all n\in\mathbb{N},3|(4^n+5). This tells us that 3 divides 4^n+5 with a remainder of zero.

If we let n=1, then we have 4^{1}+5=9, and evidently, 9|3.

Assume that 4^n+5 is divisible by 3 for n=k, k\in\mathbb{N}. Then, by this assumption, 3|(4^n+5)\Rightarrow4^k+5=3m,\: m\in\mathbb{Z}.

Now, let n=k+1. Then:

4^{k+1}+5=4^k\cdot4+5\\=4^k(3+1)+5\\=3\cdot4^k+4^k+5\\=3\cdot4^k+3m\\=3(4^k+m)

Since 3|(4^k+m), we may conclude, by the axiom of induction, that the property holds for all n\in\mathbb{N}.

3 0
2 years ago
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