Answer:
You will need 450 cells (3 cm each) to meet the voltage/current requirement.
The panel must be 3 cells in one side, by 150 cell in another side. 1350 cm^2 or 0.135 m^2. They must be connected 3 in row in parallel (to add current), then each of the former group must be connected in series to meet the voltage, so it would be 150 rows of connected in series.
The panel can be optimized using a voltage inverter, to convert current to voltage. In this way, less cells can be used achieving the same output specs.
Explanation:
To meet the voltage:
120 [v] required voltage
0.8 [v] voltage of each cell
![\frac{120}{0.8} =150[v]\\](https://tex.z-dn.net/?f=%5Cfrac%7B120%7D%7B0.8%7D%20%3D150%5Bv%5D%5C%5C)
So we need 150 cells in series for the voltage.
To meet the current
1.0 [A] Required current
350[mA]=0.35[A] cell current
1/0.35=3 cell So we need 3 cells in parallel to add the currents and meet the requirement.
See the attached figure
Answer:
<h2>1139.5 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
work done = 265 × 4.3 = 1139.5
We have the final answer as
<h3>1139.5 J</h3>
Hope this helps you
<span>To find the gravitational potential energy of an object, we can use this equation:
GPE = mgh
m is the mass of the object in kg
g = 9.80 m/s^2
h is the height of the object in meters
GPE = mgh
GPE = (0.700 kg) (9.80 m/s^2) (1.5 m)
GPE = 10.3 J
The gravitational potential energy of this can is 10.3 J</span>
Answer:
3.8 secs
Explanation:
Parameters given:
Acceleration due to gravity, g = 9.8 
Initial velocity, u = 11.76 m/s
Final velocity, v = 49 m/s
Using one of Newton's equations of linear motion, we have that:

where t = time of flight of arrow
The sign is positive because the arrow is moving downward, in the same direction as gravitational force.
Therefore:

The arrow was in flight for 3.8 secs
Answer:
I think it's no. 3
Decrease the volume of the horizontal and vertical stabilizer material.
Explanation:
Lemme know if it's correct