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emmainna [20.7K]
3 years ago
11

Air "breaks down" when the electric field strength reaches 3×106n/c, causing a spark. a parallel-plate capacitor is made from tw

o 4.0-cm-diameter disks.
Physics
1 answer:
aalyn [17]3 years ago
4 0
Ok, I think this is right but I am not sure:
 Q = ϵ
 0AE
A= π π
 r^2

=(8.85x10^-12 C^2/Nm^2)
( π π (0.02m)^2)
(3x10^6 N/C) =3.3x10^-8 C = 33nC N = Q/e = (3.3x10^-8 C)/(1.60x10^-19 C/electron) = 2.1x10^11 electrons


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A particle moving along the x-axis has its position described by the function x=(3.00t3−1.00t 2.00)m where t is in s. at t = 4.0
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X =(3.00x4.00 x3-1.00t x 2.00) x m

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3 years ago
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the mo
Svetllana [295]

Answer:

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

Explanation:

We can find the gravitational potential energy using the following  formula.

GPE=mgh

Identifying given information.

The nickel has a mass m=0.005 \,kg, and it is a the top of Washington Monument.

The Washington Monument has a height of h=555 \, ft, thus we need to find the equivalence in meters using unit conversion in  order to find the gravitational potential energy.

Converting from feet to meters.

Using the conversion factor 1 m = 3.28 ft, we have

h = 555 \, ft \times \cfrac{1 \, m}{3.28 \, ft}

That give u s

h = 169.2 \, m

Finding Gravitational Potential Energy.

We can replace the height and mass on the formula

GPE=mgh

And we get

GPE=(0.005)(9.8)(169.2) \, J

\boxed{GPE=8.29 \,J}

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

7 0
3 years ago
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To determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. it is found th
il63 [147K]

The difference in weight is due to the displacement of water (the buoyancy of water is acting on the athlete thus giving her smaller weight).<span>

The amount of weight displaced or the amount of buoyant force is: </span>

Fb = 690 N - 48 N

Fb = 642 N

From newtons law, F = m*g. Using this formula, we can calculate for the mass of water displaced:

m of water displaced = 642N / 9.8m/s^2

m of water displaced = 65.5 kg

Assuming a water density of 1 kg/L, and using the formula volume = mass/density:

V of water displaced = 65.5kg / 1kg/L = 65.5 L

The volume of water displaced is equal to the volume of athlete. Therefore:

V of athlete = 65.5 L

The mass of athlete can also be calculated using, F = m*g

m of athlete = 690 N/ 9.8m/s^2

m of athlete = 70.41 kg

 

Knowing the volume and mass of athlete, her average density is therefore:

average density = 70.41 kg / 65.5 L

<span>average density = 1.07 kg/L = 1.07 g/mL</span>

5 0
3 years ago
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A student pushes a box with a total mass of 50 kg. What is the net force on the box if it accelerates 1.5 m/s
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We now that follow newton rules f=ma so net force equal to mass*acceleration=>f=50*1.5=75 N
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