I think it is a Anursa or momentum
Answer:
C, A fast charging rhinoceros
Explanation:
took the test and got 100%
The angular frequency of the cyclotron is 0.07 x Hz.
<h3>What is angular frequency?</h3>
- Angular frequency, abbreviated "ω" is a scalar measure of rotation rate in physics.
- It describes the rate of change of the argument of the sine function, the rate of change of the phase of a sinusoidal waveform, or the angular displacement per unit of time.
<h3>What is cyclotron?</h3>
The cyclotron device is made to accelerate charge particles to extremely high speeds by applying crossed electric and magnetic fields.
<h3>Calculation of angular frequency:</h3>
Given,
B = 0.47 T
r = 0.68
mass of proton = 1.6x
q = 1.6 x
so, the frequency is:
f = qB/2m
f = 1.6 x x 0.47/2x3.14x1.6x
f = 0.07 x
Hence, the angular frequency of the cyclotron is 0.07 x Hz.
Learn more about angular frequency here:
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Answer:
Let's begin by explaining that <u>a primary color is one that can not be obtained by mixing any other color.
</u>
In this sense, red, green and blue are the primary colors of light (using the additive theory of color), <u>but not the primary colors of the pigments.
</u>
For the case of pigments (using the <u>subtractive color theory</u>) the primary colors are cyan, magenta and yellow. This is because the pigments generally absorb more light than they reflect (they absorb certain wavelengths and reflect others). Therefore, the color that a given object seems to have depends on which parts of the visible electromagnetic spectrum are reflected and which parts are absorbed.
Hence, according to the subtractive theory, if we join the three primary colors of the pigments, we will obtain the black. Unlike the additive theory of light, in which if we join the three primary colors we will get white light.
The minimum coefficient of friction to avoid slippage of the coin is 0.23.
<h3>
Minimum coefficient of friction</h3>
The minimum coefficient of friction can determined from the maximum speed of the coin.
ma = μmg
mv²/r = μmg
v²/r = μg
v² = μgr
μ = v²/(gr)
μ = (ωr)²/(gr)
μ = ω²r/g
μ = (7.95² x 0.035)/(9.8)
μ = 0.23
Learn more about coefficient of friction here: brainly.com/question/20241845
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