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2 years ago

14

A block slides down a frictionless plane that makes an angle of 24.0° with the horizontal. What is the

1 answer:

irga5000 [103]2 years ago

7 0

Answer:

F = m g sin theta force accelerating block

m a = m g sin theta

a = 9.8 sin 24 = 3.99 m/sec^2

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explain how the temperature of the earth is maintained and how it’s affected by other factors (6 marks)

nikklg [1K]

Answer:

The temperature of the Earth depends on many factors, including the concentration of greenhouse gases such as water vapour, methane and carbon dioxide. The Earth's temperature also depends on the rates at which light radiation and infrared radiation are: absorbed by the Earth's surface and atmosphere.

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2 years ago

On the moon, the acceleration of gravity is 1.6 m/s2. If an object has a

Amanda [17]

Answer:

5.1 kg

Explanation:

Its mass on the moon is 5.1 kg because mass is an intrinsic property of a material and does not change with location. Although, its weight might vary because its acceleration of gravity g is dependent on the mass M and radius r of the planet(in this case, moon) involved g = GM/r². Since weight W = mg is dependent o g, weight varies but mass remains constant.

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3 years ago

Suppose you have a 0.750-kg object on a horizontal surface connected to a spring that has a force constant of 150 N/m. There is

marshall27 [118]

Answer:

$x=0.0049\ m= 4.9\ mm$

$d=0.01153\ m=11.53\ mm$

Explanation:

Given:

mass of the object, $m=0.75\ kg$

elastic constant of the connected spring, $k=150\ N.m^{-1}$

coefficient of static friction between the object and the surface, $\mu_s=0.1$

(a)

Let x be the maximum distance of stretch without moving the mass.

<em>The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.</em>

$f=k.x$

$\mu_s.N=k.x$

where:

N = m.g = the normal reaction force acting on the body under steady state.

$0.1\times (9.8\times 0.75)=150\times x$

$x=0.0049\ m= 4.9\ mm$

(b)

Now, according to the question:

Amplitude of oscillation, $A= 0.0098\ m$

coefficient of kinetic friction between the object and the surface, $\mu_k=0.085$

Let d be the total distance the object travels before stopping.

<em>Now, the energy stored in the spring due to vibration of amplitude:</em>

$U=\frac{1}{2} k.A^2$

<u><em>This energy will be equal to the work done by the kinetic friction to stop it.</em></u>

$U=F_k.d$

$\frac{1}{2} k.A^2=\mu_k.N.d$

$0.5\times 150\times 0.0098^2=0.0850 \times 0.75\times 9.8\times d$

$d=0.01153\ m=11.53\ mm$

<em>is the total distance does it travel before stopping.</em>

7 0

2 years ago

*need help asap! on a timer* Please select the word from the list that best fits the definition

GarryVolchara [31]

Answer:

particle model

Explanation:

A particle model is a simplified version of a motion diagram in which the object in motion is replaced by a series of single points.

7 0

3 years ago

The inductor in the RLC tuning circuit of an AM radio has a value of 250 mHmH . You may want to review (Pages 857 - 860) . Part

ANEK [815]

Answer:

The value of variable capacitor is $1.89 \times 10^{-13}$ F

Explanation:

Given :

Inductance $L = 250 \times 10^{-3}$ H

Frequency $f = 731 \times 10^{3}$ Hz

According to the cutoff frequency,

$f = \frac{1}{2\pi \sqrt{LC} }$

Now we find the value of capacitance,

$C = \frac{1}{4\pi ^{2} f^{2} L }$

$C = \frac{1}{4\times 9.85 \times (731 \times 10^{3} )^{2} \times 250 \times 10^{-3} }$

$C = 1.89 \times 10^{-13}$ F

Therefore, the value of variable capacitor is $1.89 \times 10^{-13}$ F

6 0

3 years ago