Answer:
70
Step-by-step explanation:
= First term = 
= Common difference = 
= Number of terms = 20
Sum of arithmetic progression is given by
![S=\dfrac{n}{2}[2a_1+(n-1)d]\\\Rightarrow S=\dfrac{20}{2}\times (2\times \dfrac{1}{3}+(20-1)\dfrac{1}{3})\\\Rightarrow S=70](https://tex.z-dn.net/?f=S%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a_1%2B%28n-1%29d%5D%5C%5C%5CRightarrow%20S%3D%5Cdfrac%7B20%7D%7B2%7D%5Ctimes%20%282%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%2B%2820-1%29%5Cdfrac%7B1%7D%7B3%7D%29%5C%5C%5CRightarrow%20S%3D70)
The sum of the first 20 terms of the arithmetic sequence is 70.
Answer:
does not exist
Step-by-step explanation:
According to the divergence test, for an infinite series ∑ aₙ, the series diverges if lim(n→∞) aₙ ≠ 0.
Applying the divergence test here:
lim(n→∞) (3n⁵ / (4n⁵ + 1)) = 3/4
This is not 0, so the series does not converge, meaning the sum does not exist.
C=11/35
You subtract 4/35 from both sides.
Answer:
N= -4
Step-by-step explanation:
Answer:
Step-by-step explanation:
1 3/5 + 2 5/10 = 26/10 +25/10 = 51/10
