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2 answers:
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Answer:
Yearly sales in 1990: $98,800.
Step-by-step explanation:
We have been given that the sales of a certain appliance dealer can be approximated by a straight line. Sales were $6000 in 1982 and $ 64,000 in 1987.
If at 1982, then at 1987 x will be 5.
Now, we have two points (0,6000) and (5,64000).
Now, we will represent this information in slope-intercept form of equation.
, where,
m = Slope,
b = Initial value or y-intercept.
We have been given that at , the value of y is 6,000, so it will be y-intercept.
Substitute values:
Therefore, the equation represents yearly sales.
Now, we will find difference between 1990 and 1982.
To find yearly sales in 1990, we will substitute in the equation.
Therefore, the yearly sales in 1990 would be $98,800.
Answer:
1. In the multiplication of the imaginary parts, the student forgot to square of i. OR
2. The student has only multiplied the real parts and the imaginary parts.
Correct value .
Step-by-step explanation:
The given expression is
A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.
Student's mistake can be either 1 or second:
1. In the multiplication of the imaginary parts, the student forgot to square of i.
2. The student has only multiplied the real parts and the imaginary parts.
Which is not correct. The correct steps are shown below.
Using distributive property, we get
Therefore, the correct value of is
.