The given logarithmic equation solved for x is x = 10
<h3>Solving Logarithmic equations</h3>
From the question, we are to solve the given logarithmic equation.
The given logarithmic equation is
log((4x)/(8)) = log(x - 5)
To solve the given logarithmic equation, we will determine the value of the unknown variable.
The unknown variable in the equation is x.
From one of the rules of logarithm, we have that
If logₓY = logₓZ
Then,
Y = Z
Thus,
From log((4x)/(8)) = log(x - 5)
We can write that
(4x)/(8) = (x - 5)
Now, solve for x
(4x)/(8) = (x - 5)
Multiply both sides by 8
8 × (4x)/(8) = (x - 5) × 8
4x = 8x - 40
Subtract 8x from both sides of the equation
4x - 8x = 8x - 8x - 40
-4x = -40
Multiply both sides by -1
-1 × -4x = -1 × -40
4x =40
Divide both sides by 4
4x/4 = 40/4
x = 10
Hence, the solution of the equation is x = 10
Learn more on Solving logarithmic equation here: brainly.com/question/237323
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Answer:
x=1
Step-by-step explanation:
Convert decimals to fractions:
11/5x + 11/5 / 4= 1.1
Simplifies the fraction:
11x+11 / 20= 1.1
Remove denominator (then multiply by 20 on both sides):
11x+11=22
Move the x to the left:
11x= -11+22 → 11x=11
Simplify:
11x=11 → x=1
Answer:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved
Step-by-step explanation:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)
Consider x^2-2/3x+1/3
Remember that (a-b)^2 =a^2-2ab+b^2
x^2=a^2
a=x
-2/3x= -2*x*b
b=1/3
S0 (x-1/3)^2= x^2-2/3x+1/9
x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved
Answer:
7/3 =x
Step-by-step explanation:
2x+3=5x-4
Subtract 2x from each side
2x-2x+3=5x-2x-4
3 = 3x -4
Add 4 to each side
3+4 = 3x
7 = 3x
Divide by 3
7/3 =3x/3
7/3 =x
