Let x be the length and y be the width2x + 2y = 40x + y = 20change that into y = mx + b formy= 20 – x
Area =xy = x (20-x) = 20x - x^2Area=-x^2+20xcomplete the square:Area=-(x^2 – 20x + 100) +100=-(x - 10)^2 + 100This is an calculation of a parabola that opens downward with vertex at (10,100), which means maximum area of 100 happens when x, the length=10)Dimensions of the rectangle with maximum area? 10 yds. by 10 yds., a square.
Answer:
egh
Step-by-step explanation:
Answer:
∠ BXC = 70°
Step-by-step explanation:
∠ XBC and ∠ AXY are corresponding angles and are congruent, then
∠ XBC = 55°
Since XB = XC , then Δ XBC is isosceles and the 2 base angles are congruent.
∠ BXC = 180° - (55 + 55)° ← angle sum of triangle
∠ BXC = 180° - 110° = 70°
Answer:
83
Step-by-step explanation:
the angle with 126 is supplementary and all the angles of the triangle are supplementary
180-126 = 54
54 + 43 = 97
180 - 97 = 83
<span>y= 2x ^2 - 8x +9
</span>y = a(x - h)2 + k, where (h, k) is the vertex<span> of the parabola
</span>so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------<span>vertex form</span>
