Since M divides segment AB into a ratio of 5:2, we can say that M is 5/(5+2) of the length of AB. Therefore 5/7 × AB. distance of AB = d 5/7×(x2 - x1) for the x and 5/7×(y2 - y1) for the y 5/7×(8 - 1) = 5/7 (7) = 5 for the x and 5/7×(16 - 2) = 5/7 (14) = 10 for the y But remember the line AB starts at A (1, 2), so add 1 to the x: 5+1 = 6 and add 2 to the y: 10+2 = 12 Therefore the point M lies exactly at... A) (6, 12)
6x^3y^9/36x^3y^-2 The x^3 values cancel each other out leaving the 1/6 (1/6)y^9/(y^-2) the y^-2 causes the y^9 to turn into y^11 (9+2=11) (1/6)y^11/1 the 1/6 is multiplied by y^11 y^11/6
