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Snowcat [4.5K]
2 years ago
9

5 + 5Consider triangle ABC. Triangle A B C. Angle C is 80 degrees and angles B and A are y degrees. What is the value of y in th

e triangle? Angle y = °
Mathematics
2 answers:
Ket [755]2 years ago
6 0
The value of Angle Y is 100 because a triangle is 180 degrees and angle c is 80 which means 180 minus 80 equals 100
AleksAgata [21]2 years ago
6 0

Answer:

y=50°

Step-by-step explanation:

if all triangles add up to 180° you would subtract the angle you already know(80) from 180 which would be 100°

since there are 2 corners we dont know you would divide by 2 which would be 50°

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I need a quick answer , someone please help
devlian [24]
Measurement a is 45
measurement b is 135
4 0
2 years ago
Line 2 shows position data for an object that is speeding up. Use the centimeter ruler to measure the distance of each dot from
monitta

Answer:

1= 0

2= 0.5

3= 1.5

4= 3

5= 5

6= 7.5

7= 10.5

8= 14

explanation: This is the edmentum answer

7 0
3 years ago
Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case
olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> =  Mike will show up.

Given:

P(D^{c})=0.55\\P(M^{c})=0.45

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

                                                   =1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0
3 years ago
Read 2 more answers
Find magnitude and directionof vector a = ( -3 , -3 )​
nevsk [136]

Answer:

Step-by-step explanation:

Magnitude: |a|= \sqrt{(-3)^{2}+(-3)^{2} }=3\sqrt{2}

Direction: in the negative direction of the Ox axe and Oy axe

3 0
2 years ago
Yall help me?please and thank you
aksik [14]
It would be 27/8 = 3 3/8 next 18/5 = 3 3/5 after that 19/6 = 3 1/6 lastly 35/4 = 8 3/4
Hope this helped!

3 0
2 years ago
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