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olya-2409 [2.1K]
3 years ago
5

Can anyone help me?

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
5 0

Given:

A right angle triangle ABC, right angled at C.

To find:

The measure of θ.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Opposite}{Adjacent}

In triangle ABC,

\tan \theta=\dfrac{AC}{BC}

\tan \theta=\dfrac{2.7}{5}

\tan \theta=0.54

It can be written as

\theta=\tan^{-1}0.54

\theta\approx 28.369

Therefore, the measure of θ is 28.369.

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15pts! (Multiple choice answer)Please answer with work
MariettaO [177]

To find the area of a rectangle, we multiply the Base by the Height.                        In this case the:   Base = AB   and     Height = BC  

So to get the area, we multiply AB by BC.                                               (and we know that <em>BC = 5x+5/x+3</em> <em>and BC = [3x+9/2x-4)</em>  

So we would do:

\frac{5x+5}{x+3} x \frac{3x+9}{2x-4}                              

Note: When multiplying fractions together, we multiply the numerator by the numerator, and the denominator by the denominator.                                        

For example \frac{2}{8} x \frac{3}{4} = \frac{6}{32}    


Answer: \frac{5x+5}{x+3} x \frac{3x+9}{2x-4} = \frac{(5x+5)(3x+9)}{(x+3)(2x-4)}

\frac{(5x+5)(3x+9)}{(x+3)(2x-4)} = \frac{5(x+1)*3(x+3)}{(x+3)*2(x-2)} [<em>Note: </em><em>we are able to factorise some brackets to make the sum easier. For example we can factor out the 5 in (5x+5) to get: 5(x+1)   ]</em>

Now lets simplify by multiplying the 5 and 3 together in the numerator:

\frac{5(x+1)*3(x+3)}{(x+3)*2(x-2)} = \frac{15 (x+1)(x+3)}{(x+3)*2(x-2)}

If you notice, there is a (x+3) in numerator and the denominator. This means that we can cancel out the (x+3), to get the most simplified expression for the area:

\frac{15 (x+1)(x+3)}{(x+3)*2(x-2)} = \frac{15(x+1)}{2(x-2)}

Final Simplified Answer: \frac{15(x+1)}{2(x-2)} which is the last option

3 0
3 years ago
Read 2 more answers
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