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3 years ago

the lengths of the sides of a triangle are 2n, n^2 and n+5 for what value of n do these lengths not make a triangle ?

Mathematics

2 answers:

PtichkaEL [24]3 years ago

8 0

The length , explain that againnnnnnn

mash [69]3 years ago

3 0

Answer:

Step-by-step explanation:

Try n = 2

2n = 4

n^2 = 4

n+5 = 7 That works. It will make a triangle since the 2 smallest numbers are bigger than 7

Try n = 3

2n = 6

n^2 = 9

n + 5 = 8 That works. Same reason as above.

n = 4

2n = 8

n^2 = 16

n + 5 = 9 That works. Same reason.

n = 5

2n = 10

n^2 = 25

n+5 = 10 Aha! That doesn't work. the two smaller numbers only = 20.

There are likely many numbers that don't work. I'll try one more

n = 6

2n = 12

n + 5 = 11

n^2 = 36 This won't work either. Same reason as n = 5.

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If cos(θ)=2853 with θin Q IV, what is sin(θ)?

marysya [2.9K]

Answer: $\sin \theta=\frac{-45}{53}$

Step-by-step explanation:

Since we have given that

$\cos\theta=\frac{28}{53}$

And we know that θ is in the Fourth Quadrant.

So, Except cosθ and sec θ, all trigonometric ratios will be negative.

As we know the "Trigonometric Identity":

$\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}$

It must be negative due to its presence in Fourth quadrant.

Hence, $\sin \theta=\frac{-45}{53}$

7 0

3 years ago

The proportion of left handed people in the population is about 0.10. Suppose a random sample of 300 people is observed. (a) Wha

pantera1 [17]

Answer: $(\hat{p})\sim N(0.10,\ 0.017)$

Step-by-step explanation:

Sampling distribution of the sample proportion $(\hat{p})$ :

$(\hat{p})\sim N(p,\ \sqrt{\dfrac{p(1-p)}{n}})$

The sampling distribution of the sample proportion $(\hat{p})$ has mean = $\mu_{\hat{p}}=p$ and standard deviation = $\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}$ .