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kotykmax [81]
3 years ago
10

Wallace writes the number 72,204 in a

Mathematics
2 answers:
sveta [45]3 years ago
8 0
Thousands and write the number out too
slava [35]3 years ago
5 0

looks like the answer C. Thousands.

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What is the simplest form of StartRoot 3,025 EndRoot? 16, 55, 52(112), 52+(112)
DanielleElmas [232]
<h2>The simplest form of \sqrt{3025} is equal to 55.</h2>

Step-by-step explanation:

We have,

\sqrt{3025}

Too find, the simplest form of \sqrt{3025} = ?

∴ \sqrt{3025}

=\sqrt{5\times 5\times 11\times 11}

=\sqrt{5^2\times 11^2}

= 5 × 11

= 55

∴ The simplest form of \sqrt{3025} = 55

Thus, the "simplest form of \sqrt{3025}" is equal to 55.

6 0
3 years ago
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A company was able to increase its staff from 200 employees to 348
nexus9112 [7]

Answer:

The percent increase is 74%

Step-by-step explanation:

Copy and Paste

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3 years ago
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Which of the following is a healthy blood pressure level?
elena-s [515]
The correct answer is choice C
5 0
3 years ago
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(4x-3)(2x^2-7x+1) what is the product of this please help!
goblinko [34]

Answer:

8x^{3}-34x^{2}+25x-3

Step-by-step explanation:

In order to solve this problem, lets take the two terms in the binomial (4x and -3) and, for each one, multiply them by each term in the trinomial (2x^2, -7x, and 1):

(4x-3)(2x^{2}-7x+1)

(4x*2x^{2})+(4x*-7x)+(4x*1)+(-3*2x^{2})+(-3*-7x)+(-3*1)

8x^{3}+(-28x^{2})+4x+(-6x^{2})+21x+(-3)\\

8x^{3}-28x^{2}+4x-6x^{2}+21x-3

Let's combine like terms to get our final answer:

8x^{3}-28x^{2}-6x^{2}+4x+21x-3

8x^{3}-34x^{2}+25x-3

6 0
3 years ago
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

The value of h^\prime(1)=5

Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
3 years ago
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