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ikadub [295]
3 years ago
7

For the following reaction: Fe2O3 + 3CO --> 2Fe + 3CO2 how many grams of Fe2O3 is needed to produce 111 g of Fe?

Chemistry
1 answer:
Afina-wow [57]3 years ago
4 0
You need 158.70 grams of Fe2O3 to produce 111 grams of Fe. This is calculated by using the molar masses and stoichiometric relationship of the two compounds.

Solution:

MM Fe = 55.845 g/mol
MM Fe2O3 = 159.69 g/mol
Fe: Fe2O3 = 2 mol:1 mol

11 g FE (1 mol Fe/55.845 g Fe) (1 mol Fe2O3/2 mol Fe) (159.69 g Fe2O3 / 1 mole Fe2O3) = 158.70 grams Fe2O3
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3 years ago
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Explanation:

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a. The second run will be faster.

d. The second run has twice the surface area.

Explanation:

The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.

A=\pi ^{1/3} (6V)^{2/3}

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A=\pi ^{1/3} (6.10.0)^{2/3}=22.4cm^{2}

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A=\pi ^{1/3} (6. 1.25)^{2/3}=5.61cm^{2}

The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²

The ratio of  8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00

Since the surface area is doubled, the second run will be faster.

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3 years ago
Can liquid CO2 exist on Earth? Why or Why not ?
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