Consider a class in which there are 40 students .There is a Mathematics test of 50 marks .Two students were absent.The Duration of test was for one and half an hour.

So Marks of students according to their roll number are 12,8,4,20,25,36,2,29,35,39,5,48,43,37,38,29,17,15,15,25,31,32,26,28,27,24,2,15,34,,50,46,48,37,28,26,45,49,24.

So in this case it would be better to prepare frequency polygon by selecting a class interval.

Class interval = 0-5,5-10,10-15,15-20,20-25,25-30,30-35,35-40,40-45,45-50.

Or 0-10,10-20,20-30,30-40,40-50.

or you can make class interval by yourself.

4 0

3 years ago

monica sells lemonade over the summer and uses conical paper cups to serve the lemonade. Each cup is 8 centimeters tall.She star

GaryK [48]

Answer:

(a)205

(b)5 Packages

Step-by-step explanation:

$\text{One gallon is equivalent to 3785 } cm^3$

Therefore: $\text{10 gallon= 3785X 10 =37850 } cm^3$

Therefore, Volume of the lemonade Monica Started with is $\text{37850 } cm^3$

The diameter of the cup =8cm

Therefore, Radius =8/2 =4cm

Height of the Cup =11cm

Volume of a Cone= $\frac{1}{3}\pi r^2 h$

$\text{Volume of the Cup}=\frac{1}{3}\pi *4^2*11 \\=184.31cm^3$

The number of cups needed to empty the 10 gallon cooler =37850÷184.31

=205.36

$\approx 205$ Cups

(b)If the Cups are sold in packages of 50

Number of Package to be bought =205 ÷ 50 =4.1

She would need to buy 5 packages.

5 0

3 years ago

GARY DREW A RECTANGLE WITH A PERIMETER OF 20 INCHES. WHAT COULD BE THE LENGTH,WIDTH,AND AREA FOR THE RECTANGLE THAT GARY DREW?

Ilia_Sergeevich [38]

Assume L=1.5W, where W=width, L= Length of the triangle.

Therefore,

Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in

Then, L=1.5W = 1.5*4 = 6 in

Area, A= L*W = 6*4 = 24 in^2

8 0

3 years ago