Question

(WILL GIVE BRAINLIEST)Find the polynomial function with real coefficients that has zeros 1, 1 , 2+ i sqrt 3

Answer 1

Answer:

$x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0$

Step-by-step explanation:

We have given that this polynomial has the given zeroes of 1, 1, and $2+i\sqrt{3}$, we can express the polynomial in a factored form where each zero has the form x-a (where a is our zero):

polynomial= $(x-1) (x-1) (2+i\sqrt{3})$

                  =$(x^2+1-2x) (2+i\sqrt{3})$

                   =$x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0$