A robot moves 3\text{ m}3 m3, start text, space, m, end text, turns more than 90\degree90°90, degree clockwise, moves 4\text{ m}
4 m4, start text, space, m, end text more, turns clockwise again, then moves 3.6\,\text{m}3.6m3, point, 6, start text, m, end text. The robot ends where it started, as shown.
How far did the robot turn the first time?
Do not round during your calculations. Round your final answer to the nearest degree.
How far did the robot turn the first time?
Do not round during your calculations. Round your final answer to the nearest degree.
2 answers:
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Answer:
Dwight will take 6 hours to finish the job alone and Joe will take 3 hours to finish the job alone.
Step-by-step explanation:
Let us assume the time taken by Dwight to split a cord of firewood = K hrs
So, the per hour rate of Dwight =
As, Joe uses 3 LESS hours then Dwight.
So, the time taken by Joe to split a cord of firewood = (K- 3) hrs
So, the per hour rate of Joe =
Now, when both of them wok together, it takes them 2 hours.
So, the per hour rate of BOTH of them =
⇒ Per hour rate of ( Dwight + Joe) =
Now, solving for the value of K , we get:
Implies either K = 6 Or K = 1
But if K = 1, (K-3) = 1- 3 = -2 hours would be A CONTRADICTION.
⇒ K = 6 hours
Hence, Dwight will take 6 hours to finish the job alone and Joe will take (k-3) = (6-3) = 3 hours to finish the job alone.