1
P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
Is there anything else? Like what is the question asking?
Answer:
The probability of getting someone in the 18-21 age bracket or someone who agreed to respond
Step-by-step explanation:
The counts are as follows
Age Group No of people contacted No of refusals Total
18-21 88 8 96
22-29 240 42 282
Total 328 50 378
The probability of getting some one in the age bracket of 18-21 or some one who refused to respond is
It will call for A: One Centiliter. It's the same terms for stuff like millimeters and centimeters, 1 cm = 10 mm, 1 cl = 10 ml