All categories

2 years ago

Ixl p.2 geometry Help me get this to a 70 please

Mathematics

1 answer:

stepladder [879]2 years ago

4 0

Answer:

3 meters

Step-by-step explanation:

First, you figure out if the triangles are similar. Then, you figure out what the corresponding parts are. Use the relation that corresponding sides are proportional in order to write an equation for q. Solve it.

The angles in ΔDCE are marked the same as the angles in ΔDFB. We have named these triangles in order by the right angle, the angle with 1 arc, and the angle with 2 arcs. The lengths we are given are DC, DF, and DB, and we want to find length DE.

Arranging our equation so the unknown value is in the numerator of a proportion statement, we have ...

DE/DB = DC/DF

q/12 = 4/16

q = 12(4/16)

q = 3 . . . . meters

You might be interested in

Solve the equation-

trasher [3.6K]

Answer:

fgggg

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

3×the fraction blank 3 =1

Sedaia [141]

Answer:

1/3

Step-by-step explanation:

3 in fraction form =3/1

and 3/1 x 1/3= 3/3 or 1

3 0

3 years ago

What is (f−g)(x)?

Oxana [17]

Answer:

$\large\boxed{(f-g)(x)==3x^5-2x^4-x^2+x-21}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)\\\\\text{We have}\\\\f(x)=3x^5+6x^2-5\\\\g(x)=2x^4+7x^2-x+16\\\\\text{substitute:}\\\\(f-g)(x)=(3x^5+6x^2-5)-(2x^4+7x^2-x+16)\\\\=3x^5+6x^2-5-2x^4-7x^2+x-16\\\\\text{combine like terms}\\\\=3x^5-2x^4+(6x^2-7x^2)+x+(-5-16)\\\\=3x^5-2x^4-x^2+x-21$

6 0

3 years ago

The following are two sets of class scores (you may consider these scores to be normally distributed). Julia received the two sc

Pachacha [2.7K]

Find the average of all the tests on the first and second test. You find the average by adding up all the test scores and dividing it by the number of test scores you added. Then you can see if she did better than the overal average on each of the tests

3 0

3 years ago

Find the measure or angle xyz

blagie [28]

Answer:

The answer to your question is: 85°

Step-by-step explanation:

Data

m∠ xyz = 2m∠x - 9

m∠w = 38°

Process

∠x = (∠xyz + 9) / 2

∠ y = 180 - ∠xyz

∠w + ∠y + ∠x = 180

Substitution 38 + (180 - ∠xyz) + (∠xyz + 9) / 2 = 180

76 + 360 - 2∠xyz + ∠xyz + 9 = 360

Simplify

85 - 2∠xyz + ∠xyz = 0

85 = ∠ xyz

5 0

3 years ago