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Kryger [21]
3 years ago
5

a persons eardrum has an area of 0.000200 m^2. How much force does the outside air at 1.00 atm exert on the eardrum

Physics
1 answer:
alexdok [17]3 years ago
5 0

Answer:

20.3N

Explanation:

Given parameters:

Area of the eardrum  = 0.0002m²

Pressure on the eardrum  = 1atm  = 101325Nm⁻²

Unknown:

Force exerted on the eardrum  = ?

Solution:

Pressure is the force per unit area impacted on a body.

      Pressure  = \frac{Force }{area}  

  Force  = Pressure x  area

Now insert the parameters and solve;

  Force  =  101325Nm⁻²  x  0.0002m²  = 20.3N

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Before the car launches, which objects have stored energy?
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A bike traveling initially at a speed of 32 m/s accelerates
Vika [28.1K]

<u>We are given:</u>

Initial velocity (u) = 32 m/s

Acceleration (a) = 3 m/s²

Displacement (s) = 40 m

Final Velocity (v) = v m/s

<u>Solving for the Final Velocity:</u>

from the third equation of motion:

v² - u² = 2as

<em>replacing the variables</em>

v² - (32)² = 2(3)(40)

v² = 240 + 1024

v² = 1264

v = √1264

v = 35.5 m/s

Therefore, the velocity of the bike after travelling 40 m is 35.5 m/s

4 0
3 years ago
The space shuttle is located exactly half way between the earth and the moon. Which statement is true regarding the gravitationa
sdas [7]

Answer:

The correct answer is option B)

Explanation:

Considering the given question as -

The space shuttle is located exactly half way between the earth and the moon. Which statement is true regarding the gravitational pull on the shuttle? A) The moon pulls more on the shuttle. B) The earth pulls more on the shuttle. C) Both are equal due to equal distances. D) Both are equal due to the mass of the shuttle.

We know that gravitational pull (F) between any two bodies of mass M_{1} and M_{2} is given by -

F = \dfrac{GM_{1}M_{2} }{r^{2} } where 'r' is the distance between the two bodies.

Let ,

M_{e} : Mass of the earth

M_{m} : Mass of the moon

          m            : Mass of the satellite

r_{e}    : Distance of satellite from earth

r_{m}   : Distance of satellite from moon

Given that r_{e}=r_{m}

Let r_{e}=r_{m}=r

Force on satellite by the earth is -

F_{e} = \dfrac{GM_{e}m }{r^{2} }

Force on satellite by the moon is -

F_{m} = \dfrac{GM_{m}m }{r^{2} }

∵ Mass of earth (M_{e}) > Mass of moon (M_{m})

∴ F_{e} > F_{m}

∴ The gravitational pull of earth on satellite is more than that of the moon.

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4 years ago
A 6 cm long spring extends to 9 cm when a 1 kg load is suspended from it. What would be its length if a 2 kg load were suspended
Ganezh [65]
The answer is D that is the right question
8 0
3 years ago
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