Before the car launches, which objects have stored energy?

At a fabrication plant, a hot metal forging has a mass of 75kg and a specific heat capacity of 430 J/(kg.C°). Toharden it, the f

zzz [600]

Answer:

The initial temperature of the metal is = 938.63 °C

Explanation:

Heat lost by the metal = heat gained by the oil.

c₁m₁(T₁-T₃) = c₂m₂(T₃-T₂)................ equation 1

making T₁ the subject of the equation.

T₁ = [c₂m₂(T₃-T₂) + c₁m₁T₃]/c₁m₁.............. Equation 2

Where c₁ = specific heat capacity of the metal, m₁ = mass of the metal, c₂ = specific heat capacity of oil, m₂ = mass of oil, T₁ = initial temperature of the metal, T₂ = initial temperature of the oil, T₃ = Equilibrium temperature.

Given: c₁ = 430 J/kg.°C, m₁ = 75 kg, c₂ = 2700 J/kg.°C, m₂ = 710 kg, T₂ = 32°C, T₃ = 47 °C

Substituting These values into equation 2,

T₁ = [2700×710×(47-32) + 430×75×47]/(430×75)

T₁ = (28755000+1515750)/32250

T₁ = 30270750/32250

T₁ = 938.63 °C

Thus the initial temperature of the metal is = 938.63 °C

7 0

3 years ago

How many hours would it take for a single prokaryote, dividing every 20 minutes by binary fission in a favorable environment, to

butalik [34]

Answer:

$170\frac{2}{3} hrs$

Explanation:

in every 20 minutes the prokaryote divides to produce one of itself .

Mathematically,

20 mins:1 of its kind

x mins :512 of its kind

Where x is the amount of time (in minutes) needed by the prokaryote to produce 512 of its kind.

This implies that,

By cross multiplying we obtain,

$x = 20 \times 512 = 10240mins$

We now convert the time in minutes into hours.

Knowing very well that 60 minutes equals an hour, to convert 10240 minutes to hour we divide by 60.

This implies that,

$10240 \div 60 = 170 \frac{2}{3}$

8 0

3 years ago

Which best describes a force?

Alika [10]

Answer:

D is the answer

Explanation:

6 0

3 years ago

Read 2 more answers

An inductor is connected to the terminals of a battery that has an emf of 12.0V and negligible internal resistance. The current

sweet-ann [11.9K]

Answer:

PartA) resistance R=1.86Ω

PartB) inductnce L=1.26mH

Explanation:

In an RL circuit, $i(t)=\frac{E}{R}(1-e^{\frac{-t}{\frac{L}{R}}})$

where E is the emf of battery

L is inductance of inductor

R is the internal resistance of inductor

given $i(\infty)=$ $i$ max= $\frac{E}{R}$

⇒ $6.45=\frac{E}{R}$

⇒ $6.45=\frac{12}{R}$

⇒ $R=\frac{6.45}{12}=1.86$ Ω

given $i(0.94ms)=4.86$

⇒ $4.86=6.45(1-e^{\frac{-0.94*10^{-3}}{\frac{L}{R}}})$

⇒ $0.75=1-e^{\frac{-0.94*10^{-3}}{\frac{L}{R}}}$

⇒ $0.25=e^{\frac{-0.94*10^{-3}}{\frac{L}{R}}}$

applying logarithm on both sides,

⇒ $log(0.25)=\frac{-0.94*10^{-3}}{\frac{L}{R}}$

⇒ $log(4)=\frac{0.94*10^{-3}}{\frac{L}{1.86}}$

⇒ $L=\frac{0.94*10^{-3}*1.86}{log4}=1.26mH$

6 0

3 years ago

Two parallel, metal plates with separation distance d = 1.00 cm carry charges of equal magnitude but opposite sign. The plates a

Ratling [72]

Answer:

g

Explanation:

7 0

3 years ago