Question

What is the concentration of a solution made by combining 52 grams of NaCH3COO with 150 mL of water?

Answer 1

Answer: The concentration of a solution made by combining 52 grams of  $NaCH_{3}COO^{-}$ with 150 mL of water is 4.22 M.

Explanation:

Given: Mass = 52 grams

Volume = 150 mL (1 mL = 0.001 L) = 0.150 L

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

Hence, moles of $NaCH_{3}COO^{-}$ (molar mass = 82.034 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{52 g}{82.034 g/mol}\\= 0.633 mol$

Therefore, concentration of given solution is as follows.

$Molarity = \frac{moles}{Volume(in L)}\\= \frac{0.633 mol}{0.150 L}\\= 4.22 M$

Thus, we can conclude that the concentration of a solution made by combining 52 grams of  $NaCH_{3}COO^{-}$ with 150 mL of water is 4.22 M.