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3 years ago

What is the slope of the line that contains these points? PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ PLZ HELP

Mathematics

1 answer:

juin [17]3 years ago

4 0

Answer:

choose two points. (13, 11) and ( 14, 6)

use the slope formula (y2-y1)/(x2-x1)

and then plug it in and solve

(6 -11)/ ( 14-13)

-5/ 1

the slope is -5

Step-by-step explanation:

I hope this helps :)

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Find the mean of the first four test scores first.
(Add all numbers in set and divide by how many numbers there are)
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81 + 87 + 71 + 89 + 85 = 413 / 5 = 82.6

The impact that the 85 had on the mean test score was that the mean/average increased by 0.6.

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3 years ago

Read 2 more answers

The quotient of a number and 6 is less than 20.

ozzi

Answer:

$\frac{x}{6}$ < 20

Step-by-step explanation:

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3 years ago

What to do ??<br> i need help please <br> asap <br> one question left

maks197457 [2]

Answer: $(x^{\frac{2}{7}})(x^{\frac{3}{5}})$

Step-by-step explanation:

If you took the nth root of x, it is the same as raising x to the power of 1/n. Therefore:

$\sqrt[7]{x^{2} } = (x^{2} )^{1/7} = (x^{\frac{2}{7}})\\\sqrt[5]{x^{3} } = (x^{3} )^{1/5} = (x^{\frac{3}{5}})$

And multiply:

$(x^{\frac{2}{7}})(x^{\frac{3}{5}})$

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3 years ago

Directions: Simplify the following monomials.SHOW ALL STEPS!

Elena-2011 [213]

Answer:

Please see the attached images for explanation:

Step-by-step explanation:

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2 years ago

NAND"" and ""NOR"" circuits are commonly used as a basis for flash memory chips. A NAND B is defined to be the negation of ""A a

Anit [1.1K]

Answer:

(i) A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.

Since A ∧ B (the symbol ∧ means A and B) is true only when both A and B are true, its negation A NAND B is true as long as one of A or B is false.

Since A ∨ B (the symbol ∨ means A or B) is true when one of A or B is true, its negation A NOR B is only true when both A and B are false.

Below are the truth tables for NAND and NOR connectives.

(ii) To show that (A NAND B)∨(A NOR B) is equivalent to (A NAND B) we build the truth table.

Since the last column (A NAND B)∨(A NOR B) is equal to (A NAND B) it follows that the statements are equivalent.

(iii) To show that (A NAND B)∧(A NOR B) is equivalent to (A NOR B) we build the truth table.

Since the last column (A NAND B)∧(A NOR B) is equal to (A NOR B) it follows that the statements are equivalent.

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3 years ago