<span>ultraviolet light for sure is the right answer </span>
Answer:
1331.84 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity = 0
s = Displacement = 490 km
a = Acceleration
g = Acceleration due to gravity = 1.81 m/s² = a
From equation of linear motion

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km
Answer:
Maximum speed of the car is 26.56 m/s.
Explanation:
Given that,
Mass of the car, m = 1200 kg
Radius of the curve, r = 90 m
The coefficient of friction between tires and the road is 0.8.
We need to find the maximum speed of the car. On the circular curve, the centripetal force is balanced by the force of friction. So,

So, the maximum speed of the car is 26.56 m/s.
Distance from the sun.
<span>The third law of planetary motion states that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit</span>. The semi-major axis is the distance from the sun to the epicenter of the ellipse (which would be the planet in question). So, the revolutionary period is directly related to the distance of the planet from the sun.
Cold weather as in snow, and sleet. Hethared weather as in warm sun acting as a proper radiant agains the surface of biofuse, and standard quadrullants as in rain.