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Lelechka [254]
3 years ago
8

Hydrogen is in Group 1A of the periodic table, known as the alkali metals, although it obviously isn't a metal. What is the reas

on for its placement in this group?
Physics
1 answer:
jeka57 [31]3 years ago
6 0
It's highly reactive and contains only one valence electron
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What would be new resistance if length of conductor is doubled and thickness is halved <br>​
nignag [31]

Answer:

The new resistance comes out to be = 4 times of original resistance .

6 0
3 years ago
49. A block is pushed across a horizontal surface with a
nata0808 [166]

Answer:

(a) 37.5 kg

(b) 4

Explanation:

Force, F = 150 N

kinetic friction coefficient = 0.15

(a) acceleration, a = 2.53 m/s^2

According to the newton's second law

Net force = mass x acceleration

F - friction force = m a

150 - 0.15 x m g = m a

150 = m (2.53 + 0.15 x 9.8)

m = 37.5 kg

(b) As the block moves with the constant speed so the applied force becomes the friction force.

F = \mu m g \\\\150 = \mu\times 37.5\\\\\mu = 4

8 0
3 years ago
Which of the following examples could this free body diagram describe? (Check all that apply)
boyakko [2]

Answer:

A car accelerating to the right

Explanation:

The free-body diagram shows all the forces acting on an object. The length of each arrow is proportional to the magnitude of the force represented by that arrow.

In this free-body diagram, we see that there are 4 forces acting on the object, in 4 different directions. We also see that the two vertical forces are equal so they are balanced, while the force to the rigth is larger than the force to the left: this means that there is a net force to the right, so the object is accelerating to the right.

Therefore, the correct answer is:

A car accelerating to the right

5 0
4 years ago
Lee has a mass of 40.0 kg and ice skates with a speed of 4.6 m/s.
faltersainse [42]

Their common speed is 1.53 m/s.

<h3>What is speed?</h3>

Speed can be defined as the ratio of the distance to the time of a body in motion.

  To calculate their final speed, we use the formula below.

Formula:

  • mu+m'u' = V(m+m')............. Equation 1

Where:

  • m = mass of the Lee
  • m' = mass of Mat
  • u = initial speed of Lee
  • u' = initial speed of Mat
  • V = Their common speed.

make V the subject of the equation

  • V = (mu+m'u')/(m+m')........... Equation 2

From the question,

Given:

  • m = 40 kg
  • m' = 80 kg
  • u = 4.6 m/s
  • u' = 0 m/s

Substitute these values into equation 2

  • V = [(40×4.6)+(80×0)]/(40+80)
  • V = 184/120
  • V = 1.53 m/s.

Hence, Their common speed is 1.53 m/s.

Learn more about speed here: brainly.com/question/3004254

6 0
2 years ago
If 35 J of work was performed in 70 seconds, how much power was used to do this task?
Irina18 [472]
P = w \times delta \: T
P = Power
W = Work
Delta T = Change of Time

So:
P = 35 Joules
Delta T = 70 secs
W = ?

P = 35 \div 70 \\ P = 0.5 \: watts

* Joule/Sec = Watt

Answer: The power used to do this task was 0.5 Watts.
5 0
3 years ago
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