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frozen [14]
3 years ago
11

Simplify the expression. 3z + 4 + 5z minus 9

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0
3z + 4 + 5z - 9

8z - 5
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Help me plz I will give brainliest
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Hunter's class voted on whether or not to do science fair projects in groups. 30% of the 40 votes were in favor of working in gr
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3 years ago
Tom simplified an expression in three steps, as shown: x to the power of negative 2 multiplied by y to the power of 4, over y mu
ss7ja [257]

Answer:

  • Step 1, all the exponents are increased by 4

Step-by-step explanation:

<u>The three steps are</u>

  1. (x⁻² × y⁴ /y × x⁴ × x⁴ × y⁻²)⁴ =  
  2. x²×y⁸/y⁴×x⁸×x⁸×y² =
  3. x²×y⁸/y⁶×x¹⁶

<u>Correct solution should be:</u>

  • (x⁻² × y⁴ /y × x⁴ × x⁴ × y⁻²)⁴ =  all powers inside the parenthesis should be multiplied by 4 as per power of the power  (xᵃ)ᵇ = xᵃᵇ

<u>This would give next steps:</u>

  1. x⁻⁸×y¹⁶/y⁴×x⁸×x⁸×y⁻⁸ =
  2. x⁻⁸×y¹⁶/x¹⁶×y⁻⁴ =
  3. y²⁰/x²⁴

<u>Answer options:</u>

Step 1, all the exponents are increased by 4

  • There should be multiplication of powers. (It is close option but is not fully correct as not all the exponents increased by 4, for example y became y⁴)

Step 2, the exponents of the same base are added during multiplication

  • It was done correctly

Step 3 wasn't performed yet, there was step 1 and 2.

  • So answers about step 3 are irrelevant
5 0
3 years ago
A carnival game allows a group of players to each draw and keep a marble from a bag. The bag contains 5 gold marbles, 25 silver
laila [671]
1. What’s the probablity of a second person winning the small prize?
There are now 99 total marbles, and 24 silver marbles. So, 24/99 is 0.24 probability.
2. Which player is most likely to win a big prize?
Since each player draws a silver marble (aka a small prize) there are less small prize marbles in the bag after each turn. So, the first person would have a 5% chance (or 0.05)of winning the big prize gold marble, but the last person would have a slightly bigger chance (5.15% or 0.0515) of winning a big prize.
3. How could the game be made fair for each player?
Well it’s quite simple, just have each player return their marble and the number of marbles would be kept constant, giving everyone an equal chance. Or you could have them all play at the same time, either way.
4. Same answer as 3
3 0
4 years ago
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