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yarga [219]
4 years ago
11

What is the value of the function f(x)=10x+2?

Mathematics
1 answer:
Nookie1986 [14]4 years ago
7 0

Answer:

2 if x=0

Step-by-step explanation:

A function is an equation that has only one answer for y for every x. A function assigns exactly one output to each input of a specified type.

f(x) = 10x + 2

Replacing f(x) with y

y = 10x + 2

If x = 2,

y = 10(0)+2

y=2

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Which step will translatef(x)=3^xto g(x)=3^x+1 +4
vladimir1956 [14]

Answer:

step 3

Step-by-step explanation:

7 0
3 years ago
Please help i have to finish 15 assignments today including a final exam and i dont know what im doing
Sergio039 [100]

Answer:

(-1,6) ; (-2,11)

Step-by-step explanation:

y= x^2-2x +3

y= -5x + 1

the best way to proceed is substitute the value of y shows in the second equation in the first equation (general rule: substitute the value shows in the linear equation in the quadratic equation)

-5x + 1 = x^2-2x+3

x^2 +3x + 2 = 0

(x+2)(x+1) = 0

x = -2

x = -1

Solution 1

x = -1

y = 5 + 1 = 6

Solution 2

x = -2

y = 10 + 1 = 11

5 0
3 years ago
Prove it. this question is from trigonometry ​
konstantin123 [22]

Answer:

See below for step-by-step proof.

Step-by-step explanation:

\textsf{Given expression}:

\cos^6 \theta+\sin^6 \theta

\textsf{Apply exponent rule} \quad a^{bc}=(a^b)^c:

\implies (\cos^2 \theta)^3+(\sin^2 \theta)^3

\textsf{Use the identity}\quad a^3+b^3=(a+b)^3-3ab(a+b):

\implies (\cos^2 \theta+\sin^2 \theta)^3-3 \cos^2 \theta\sin^2 \theta (\cos^2 \theta+\sin^2 \theta)

\textsf{Use the identity}\quad \sin^2 \theta + \cos^2 \theta=1:

\implies (1)^3-3 \cos^2 \theta\sin^2 \theta (1)

\implies 1-3 \cos^2 \theta\sin^2 \theta

\implies 1-3 (\cos \theta\sin \theta)^2

\textsf{Use the identity}\quad \sin 2 \theta=2 \sin \theta \cos \theta \implies \dfrac{1}{2}\sin 2 \theta= \sin \theta \cos \theta:

\implies 1-3 \left( \dfrac{1}{2}\sin 2 \theta\right)^2

\implies 1-\dfrac{3}{4} \sin^2 2 \theta

\textsf{Use the identity}\quad \sin^2 2\theta + \cos^2 2\theta=1 \implies \sin^2 2\theta=1-\cos^2 2\theta

\implies 1-\dfrac{3}{4} \left(1-\cos^2 2 \theta\right)

\implies 1-\dfrac{3}{4} +\dfrac{3}{4}\cos^2 2 \theta

\implies \dfrac{1}{4} +\dfrac{3}{4}\cos^2 2 \theta

\textsf{Factor out }\dfrac{1}{4}:

\implies \dfrac{1}{4}\left(1+3\cos^2 2 \theta\right)

\textsf{Use the identity}\quad \cos (4 \theta)=2 \cos^2 2\theta - 1 \implies \cos^2 2 \theta=\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}:

\implies \dfrac{1}{4}\left(1+3\left(\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}\right)\right)

\implies \dfrac{1}{4}\left(1+\dfrac{3}{2}\cos 4 \theta+\dfrac{3}{2}\right)

\implies \dfrac{1}{4}\left(\dfrac{5}{2}+\dfrac{3}{2}\cos 4 \theta\right)

\implies \dfrac{1}{4} \cdot \dfrac{1}{2}\left(5+3\cos 4 \theta\right)

\implies \dfrac{1}{8}\left(5+3\cos 4 \theta\right)

6 0
2 years ago
Derivative of Y=cos^2(3x)
Black_prince [1.1K]
The derivative is -6sin(3x)
4 0
3 years ago
Help pls ASAP I’ll help u in return!!!!!!
Ad libitum [116K]

X/y=4

You can put it as:

y=1/4.x

Hope you get it!

4 0
4 years ago
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