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yarga [219]
3 years ago
11

What is the value of the function f(x)=10x+2?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

2 if x=0

Step-by-step explanation:

A function is an equation that has only one answer for y for every x. A function assigns exactly one output to each input of a specified type.

f(x) = 10x + 2

Replacing f(x) with y

y = 10x + 2

If x = 2,

y = 10(0)+2

y=2

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From least to greatest 0.075,75%, 3/4
krek1111 [17]

Answer:

here u go

Step-by-step explanation:

it would be  0.075,3/4, 75%

4 0
3 years ago
What is the solution, if any, to the inequality |3x|≥0?
Murljashka [212]

The inequality is all real numbers.

<h3>What is inequality?</h3>

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Given:

|3x|≥0

3x = 0

Divide both sides of the equation by the coefficient of variable

x= 0/3

x=0 = RHS

Learn more about inequality here:

brainly.com/question/20383699

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4 0
2 years ago
If a= 11, solve for b and c.
oksian1 [2.3K]

Step-by-step explanation:

b = 11

c = 11✓2 because the properties of 45 45 90 triangle

8 0
3 years ago
Noah says:
kaheart [24]
Answer: 21

Explanation:

21 - 17 = 4
4 * 8 = 32

Therefore the number is 21
4 0
3 years ago
Read 2 more answers
Two planes start flying towards each other simultaneously from two different cities. The distance between the cities is 960 mile
ANTONII [103]

Answer:

257.5 mph

332.5 mph

Step-by-step explanation:

The initial distance between the two planes is 960 miles, while the final distance (after t=1.5 h) is 75 miles, so the total distance covered by the two planes in 1.5h is

d=960-75=885 miles

Calling v1 and v2 the velocities of the two planes, we have the following equations:

(1) v_1 = v_2 + 75 --> velocity of plane 1 exceeds velocity of plane 2 by 75 mph

(2) v_1 t+ v_2 t=885 --> the total distance covered by the two planes is 885 miles (t=1.5 h is the time, and the products v1 t and v2 t represent the distance covered by each plane)

Substituting t=1.5 h, the second equation becomes:

1.5 v_1+1.5 v_2=885\\v_1 + v_2 = 590

By substituting (1) into this last equation, we find:

(v_2+75)+v_2 = 590\\2v_2 + 75 = 590\\2v_2 = 515\\v_2=257.5

And substituting this back into eq.(1), we find

v_1 = 257.5 + 75=332.5

So, the speeds of the two planes are

257.5 mph

332.5 mph



3 0
3 years ago
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