Step-by-step explanation:
The space comprising all possible outcomes (sample space) is represented by the 6×66×6 matrix formed by the possible pairs representing the outcome of dice:
From the above sample space, there are six events wherein the first die is 44 (all elements of the fourth row in the matrix). That is, n(F)=6n(F)=6. Moreover, there are six events wherein doubles are rolled (all diagonal elements in the matrix). That is, n(D)=6n(D)=6. The result (4,4)(4,4) is the intersection of both events. That is, n(D∩F)=1n(D∩F)=1.
Therefore, the possibility/probability that the first die is 4 or that doubles are rolled is computed as follows:
P(D∪F)=P(D)+P(F)−P(D∩F)=n(D)n(S)+n(F)n(S)−n(D∩F)n(S)=636+636−136=1136P(D∪F)=P(D)+P(F)−P(D∩F)=n(D)n(S)+n(F)n(S)−n(D∩F)n(S)=636+636−136=1136
Answer:
The picture was kinda blurry
Step-by-step explanation:
Assuming the ‘y’ is supposed to be x,
7 - x + 2x
7 - 6 + 2(6)
7 - 6 + 12
1 + 12
= 13
Answer:
(3700)(1+.059/12)^4(1+.172/12)^8 is the corect answer -Apex
Step-by-step explanation:
Answer: 3
Step-by-step explanation:
Take the y coordinates and divide two of them. Example: 6 ÷ 2 = 3
