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3 years ago

Please Help me With this

Mathematics

1 answer:

timofeeve [1]3 years ago

4 0

Answer:

answer : A

Step-by-step explanation:

hello :

Sin 42°= Cos(90°-42°)=cos(48°)......answer : A

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Figure A is translated 3 units right and 2 units up. The translated figure is labeled figure B. Figure B is reflected over the x

mojhsa [17]

Answer:

A Is congruent to B and B Is congruent to C

Step-by-step explanation:

Given Figures A, B and C on a coordinate plane with the coordinates below:

Triangle A has points (1, -2), (3, -2), (3, -5).

Triangle B has points (4, 0), (6, 0), (6, -3).

Triangle C has points (4, 0), (6, 0), (6, 3).

The fact that each triangle is a right triangle only shows that the triangles are similar.

For any two shapes to be congruent, they must have in addition to the same shape, the same size.

Therefore, for Triangle A to be congruent to Triangle C, Triangle A must be congruent to Triangle B and Triangle B must be congruent to Triangle C.

7 0

2 years ago

pls help! :) it’s my first day knowing about this things, i don’t even think we had a lesson on it— anywayysss

podryga [215]

Answer:

acute and equilateral

Step-by-step explanation:

because all the angles are given equal

3 0

2 years ago

Read 2 more answers

78 square ft, height is 6ft what is the base

aniked [119]

If the height is 6ft then the base is 13ft.

78/6=13

Hope this helps.

3 0

3 years ago

Find the sum of the convergent series. (round your answer to four decimal places. ) [infinity] (sin(9))n n = 1

Alexus [3.1K]

The sum of the convergent series $\sum_{n=1}^{\infty}~(sin(1))^n$ is 5.31

For given question,

We have been given a series $\sum_{n=1}^{\infty}~(sin(1))^n$

$\sum_{n=1}^{\infty}~(sin(1))^n=sin(1)+(sin(1))^2+...+(sin(1))^n$

We need to find the sum of given convergent series.

Given series is a geometric series with ratio r = sin(1)

The first term of the given geometric series is $a_1=sin(1)$

So, the sum is,

= $\frac{a_1}{1-r}$

= sin(1) / [1 - sin(1)]

This means, the series converges to sin(1) / [1 - sin(1)]

$\sum_{n=1}^{\infty}~(sin(1))^n$

= $\frac{sin(1)}{1-sin(1)}$

= $\frac{0.8415}{1-0.8415}$

= $\frac{0.8415}{0.1585}$

= 5.31

Therefore, the sum of the convergent series $\sum_{n=1}^{\infty}~(sin(1))^n$ is 5.31

Learn more about the convergent series here:

brainly.com/question/15415793

#SPJ4

7 0

1 year ago

Please help!! <br><br> Evaluate the determinant of the matrix.

kicyunya [14]

i can not give the answer unless you still cannot find it after these steps but I have steps that might help

1. Set the matrix (must be square).

2. Reduce this matrix to row echelon form using elementary row operations so that all the elements below diagonal are zero.

3. Multiply the main diagonal elements of the matrix - determinant is calculated.

5 0

2 years ago