Let us assume the number of student's in Zoe's class = x
Then
Number of students that have pets = 4x/5
Number of students that have rodents as pets = (1/8) * (4x/5)
= x/10
Number of students in Zoe's class
that have pets that are not rodents = (4x/5) - (x/10)
= (8x - x)/10
= 7x/10
I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
Answer:
Paco contributed = 360pesos
Juan contributed = 504pesos
Question:
Two brothers gathered their money to buy a gift for their dad. Between them they gathered 864, which amount each contributed if Paco gave 5 pesos for every 7 that Juan gave.
Step-by-step explanation:
Let the common factor between each brother = p
Paco gave = 5×common factor = 5p
Juan gave = 7×common factor = 7p
Total money contributed by both brothers = 864
Total money contributed by both brothers = 5p + 7p
5p + 7p = 864
12p = 864
p = 864/12
p = 72
Paco contributed = 5p = 5×72 = 360pesos
Juan contributed = 7p = 7×72 = 504pesos
Answer:
-33 or 33
Step-by-step explanation:
The seventh term of an AP is written as:
The eleventh term of an AP is written as:
If the 7th term is 11 times the 11th term, then;
Expand to get:
We must have a=-52 and d=5
Or
a=52 and d=-5
For the first case, the 18th term is :
For the second case,
Answer:
12 is 52 i think. i am not sure about 11.
Step-by-step explanation:
im so sorry i know 11:(
I hope this helps on 12 tho
