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Sauron [17]
3 years ago
5

Identify the percent, amount, and base in this problem. What percent of 80 is 40?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer:

<h2>50</h2>

Step-by-step explanation:

<h3>40: 80x100 =</h3><h3>100 =(40x100): 80 =</h3><h3>100): 80 =4000: 80 = 50</h3>

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If F(x) and 1(x) are inverse functions of each other and f(x) = 2x+5, what is (8)?
evablogger [386]

23 i used an app use should also give that a try

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3 years ago
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What is 7 times 7 + 7 ?
Basile [38]
The answer would be 98

7+7=14
14•7=98
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2 years ago
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Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
How much longer is a pencil than a glue stick
balu736 [363]

depending on the size of both i would say 3 inches

Step-by-step explanation:

4 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%2B1%3D3%5C%5C" id="TexFormula1" title="\sqrt{x} +1=3\\" alt="\sqrt{x} +1=3\\
Eduardwww [97]

Answer:

x = 4

Step-by-step explanation:

√x + 1 = 3

√x = 3 - 1

√x = 2

(√x)² = (2)²

x = 4

4 0
3 years ago
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