<span>This isn't very difficult to figure out, you just need to look at these numbers in pairs. So, 16 minus 4 is 12. Then the next pair of numbers, 36 minus 9 is 27. And to complete the pattern, you just have to look at the final pair: 44 minus 11 is 33. So the number that would complete the pattern is 33.Hope this helps. Let me know if you need additional help!</span>

6 0

3 years ago

Write an equation for the line shown in the graph

koban [17]

Answer:

y= -x+10

Step-by-step explanation:

ok, so the basic formula is y=mx+b

m=slope and b= the intercept

the line crosses the y-axis at 10, so we know that 10=b. it is a downward going slope, so its negative. the formula for slope is rise/run, or in our case, fall/run. for every 2 it falls, it runs 2. that is -2/2, which can be simplified to -1. looking at the graph , it's hard to comprehend the question at first and it took me multiple times looking at the graph. I hope I helped some!

7 0

2 years ago

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

2 years ago

Graph f(x) = 2 x + 3 + 2.

Tasya [4]

Hi this is the graph from desmos!

3 0

2 years ago

6x + 8y8y = -3114x - 5y = 46​

6x + 8y8y = -3114x - 5y = 46