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3 years ago

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You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc

over that the balloon bursts when you have pitched it to a height of 12 m. With what velocity did the balloon hit the ground? The acceleration of gravity is 9.8 m/s 2 . The positive direction is up, so the velocity when it hits is negative. Answer in units of m/s.

1 answer:

FrozenT [24]3 years ago

6 0

Answer:

The balloon hit the ground with velocity -15.34 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

burst when it hits the ground is 12 meters.

We consider that the 12 meters is the maximum height, so the velocity

at this height is zero.

To find the velocity when the balloon hits the ground lets use the rule

<em>v² = u² + 2gh</em>, where v is the final velocity, u is the initial velocity, g is

the acceleration of gravity and h is the height.

u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

v² = 0 + 2(9.8)(12)

v² = 235.2

<em>Take square root for both sides</em>

v = ± $\sqrt{235.2}$

The velocity is downward, then it's a negative value

Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

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