The answer will be C, a stopwatch :)
A solar eclipse will be visible over a wide area of the north polar region
on Friday, March 20.
England is not in the path of totality, but it's close enough so that a large
part of the sun will be covered, and it will be a spectacular sight.
For Londoners, the eclipse begins Friday morning at 8:25 AM,when the
moon just begins to eat away at the sun's edge. It advances slowly, as more
and more of the sun disappears, and reaches maximum at 9:31 AM. Then
the obscured part of the sun begins to shrink, and the complete disk is
restored by the end of the eclipse at 10:41AM, after a period of 2 hours
16 minutes during which part of the sun appears to be missing.
The catch in observing the eclipse is:
<em><u>YOU MUST NOT LOOK AT THE SUN</u></em>.
Staring at the sun for a period of time can cause permanent damage to
your vision, even though <em><u>you don't feel it while it's happening</u></em>.
This is not a useful place to try and give you complete instructions or
suggestions for observing the sun over a period of hours. Please look
in your local newspaper, or search online for phrases like "safe eclipse
viewing".
Explanation:
Heat is a form of energy that can transfer from hot body to cold body.Temperature is the degree of hotness and coldness of a body.
Heat is measured in joules, but temp. is measured in Kelvin
Answer:
d = 6.43 cm
Explanation:
Given:
- Speed resistance coefficient in silicon n = 3.50
- Memory takes processing time t_p = 0.50 ns
- Information is to be obtained within T = 2.0 ns
Find:
- What is the maximum distance the memory unit can be from the central processing unit?
Solution:
- The amount of time taken for information pulse to travel to memory unit:
t_m = T - t_p
t_m = 2.0 - 0.5 = 1.5 ns
- We will use a basic relationship for distance traveled with respect to speed of light and time:
d = V*t_m
- Where speed of light in silicon medium is given by:
V = c / n
- Hence, d = c*t_m / n
-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50
d = 0.129 m 12.9 cm
- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm
