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Eduardwww [97]
3 years ago
6

21p+35qplease help me!​

Mathematics
1 answer:
beks73 [17]3 years ago
8 0

Answer:

Simplifying

21p + 35q = 0

Solving

21p + 35q = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-35q' to each side of the equation.

21p + 35q + -35q = 0 + -35q

Combine like terms: 35q + -35q = 0

21p + 0 = 0 + -35q

21p = 0 + -35q

Remove the zero:

21p = -35q

Divide each side by '21'.

p = -1.666666667q

Simplifying

p = -1.666666667q

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If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

Thus,

t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0
3 years ago
What is the answer to -87=3(6-7x)
Butoxors [25]

Answer:

4.95238095238= x

Step-by-step explanation:

-87= 3(6-7x)

-87= 17-21x

-17  -17

-104= -21x

/-21    /-21

4.95238095238= x

4 0
3 years ago
Read 2 more answers
2 to the 3 power x 2 to the 4 power
inn [45]

Answer:

The answer is 128

Step-by-step explanation:

2³ × 2⁴ = 2⁷ ( when it comes to multiple with the same base, the power must add together)

= 128

(Correct me if i am wrong)

3 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%7Ba%20%7D%5E%7B2%7D%20%20%2B%208a%20%2B%2015%20%3D%200" id="TexFormula1" title=" {a }^{2}
NISA [10]

Answer:

a = - 5, a = - 3

Step-by-step explanation:

Given

a² + 8a + 15 = 0 ← in standard form

(a + 3)(a + 5) = 0 ← in factored form

Equate each factor to zero and solve for a

a + 3 = 0 ⇒ a = - 3

a + 5 = 0 ⇒ a = - 5

8 0
3 years ago
Hey can yall help me with this question thank you
ipn [44]

Step-by-step explanation:

a. 2x+5

b. 3x+5

c. 5x+4

i hope it will help you

7 0
3 years ago
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