To group an expression, means that the factors of the expression are to be separated in (), [] or {}.
An expression with a value of 80 is: ![2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=2%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
The number is given as:

Factorize

Factorize 40

Express
as an exponent

Express 20 as 4 x 5

Express 5 as 3 + 2
![80 = 2^2 \times ( 4 \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%204%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Express 4 as 2 + 2
![80 = 2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Hence, the above expression has a numerical value of 80
Read more about numerical expressions at:
brainly.com/question/24787226
Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
Answer:
14 minutes below or 6 minutes above
Step-by-step explanation:
Let's say Sophia's time was 10 minutes WORSE
4 minutes below average- 10 minutes= 14 minutes below average
Let's say Sophia's time was ten minutes BETTER
4 minutes below average + 10 minutes= 6 minutes above average.
Hope this helps!