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geniusboy [140]
3 years ago
13

Please write an equation in slope intercept form that is parallel to the equation

Mathematics
1 answer:
gtnhenbr [62]3 years ago
4 0

Answer:

y=1/4x-1.5

Step-by-step explanation:

So, because the line is parallel, the slope is the same. Then, to get the y-int, you do b=y-mx with the point, so the equation is b=-1-(1/4)(2), then you multiply to get b=-1-(0.5), so your y-int is -1.5.

(:P)

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AnnyKZ [126]

Answer:

Graph is Linear, Continuous function and each pound of blueberries costs $4.

Step-by-step explanation:

This is shown per the definition of a linear graph: a line that is a straight. Its a continuous function because the pounds rise with the cost continuously, with no change in slope. Its $4 because for every pound, the cost goes up by 4. Ex. 1 pd = $4, 2 pd = $8 etc.

4 0
3 years ago
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The legth of a rectangle is 15 inches less then twice its width, w. If the perimeter of the rectangle is 96 inches what is the l
KATRIN_1 [288]

Answer:

length of the rectangle=27"

Step-by-step explanation:

length be = l; width be = b

2b-15= l

perimeter= 2(l+b)

=2(2b-15+b)=96

=2(3b-15)  =96

3b-15 .=48

3b=48+15=63

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8 0
3 years ago
Can anyone answer this
Elanso [62]

Answer:

6

Step-by-step explanation:

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4 0
3 years ago
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If m∠JKP=3r+12 and m∠2=4r−2, what is ∠JKN?
Leokris [45]
The answer seems to be 108
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guapka [62]
Let the sides of the polygon (which is a triangle, by the way) be x, y and z.  The sum of x, y and z is the perimeter of the original poly, and this equals 18 cm.

Letting f be the scale factor,   f(18 cm) = 12 cm.  Then f=2/3.

The dilation reduces the size of the polygon by a factor of 1/3, producing a similar polygon which is 2/3 the size of the original one.

In each case we have 3 side lengths but no angles.  We can use Heron's formula to obtain the area in each case.  Look up Heron's formula.  In one version of this formula, p is half the actual perimeter, meaning that p is 18 cm / 2 for the first triangle and 12 cm / 2 for the second. 

The area of the first triangle would be

A18 = sqrt( 9(9-x)(9-y)(9-z) )

whereas 

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Then the ratio of the areas of the 2 triangles is

sqrt( 6(6-x*a)(6-y*a)(6-z*a) )
---------------------------------------
  sqrt( 9(9-x)(9-y)(9-z) )

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