A1) One possible set of inequalities is
x +y > 2
y -x < 4
A2) The lines are graphed as though the inequality were an equal sign. Since the inequality does not include the "or equal to" case, the lines are drawn dashed. In each case, the area to the right of the line is shaded.
B) Points A and B are solutions to the system if they are in the doubly-shaded region (which they are). In the graph here, that region is darker orange. (For this purpose, you need to ignore the green region, which overlaps part of the solution space.
C) The houses Billy is interested in are found by graphing the inequality and identifying the houses in its solution space. (Those houses are B and C.) Alternatively, you can evaluate the inequality for each of the house coordinates and see which ones give "true."
Answer:
MEOW.....................
Step-by-step explanation:
Answer:
343m3,8m3,1000m3 for Perfect squares
300m3,9m3,900m3 for Not-perfect squares
Step-by-step explanation:
Did an assignment on edge
A+b=32
4a+7b=200
a = 15
b = 20
There are 15 four pointers and 20 seven pointers. You can plug in the numbers to check.
I believe this is correct. If not i am extremely sorry.
Have a wonderful day :)
Answer:
x = sqrt(29)/2 - 3/2 or x = -3/2 - sqrt(29)/2
Step-by-step explanation by completing the square:
Solve for x over the real numbers:
x^2 + 3 x - 5 = 0
Add 5 to both sides:
x^2 + 3 x = 5
Add 9/4 to both sides:
x^2 + 3 x + 9/4 = 29/4
Write the left hand side as a square:
(x + 3/2)^2 = 29/4
Take the square root of both sides:
x + 3/2 = sqrt(29)/2 or x + 3/2 = -sqrt(29)/2
Subtract 3/2 from both sides:
x = sqrt(29)/2 - 3/2 or x + 3/2 = -sqrt(29)/2
Subtract 3/2 from both sides:
Answer: x = sqrt(29)/2 - 3/2 or x = -3/2 - sqrt(29)/2