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3 years ago

Verify experimentally that the angle opposite to the longer side is greater than

Mathematics

1 answer:

Veronika [31]3 years ago

6 0

Answer:

If two sides of a triangle are unequal, the angle opposite to the longer side is larger (or greater). You may prove this theorem by taking a point P on BC such that CA = CP.

Step-by-step explanation:

That's how you can prove which side is bigger

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5(x+21)= 8x help me please

chubhunter [2.5K]

Answer:

Step-by-step explanation:

Steps

1. 5x + 105 = 8x because you distributed the 5

2. 105 = 3x because you subtract the 5x on both sides

3. 105/3 = x because you divide the 3 and 105/3 is 35

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2 years ago

Which expression is equivalent to w4−25w2+144

eduard

Sorry I’m just commenting to do it

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3 years ago

Sherman has 3 cats and 2 dogs. He wants to buy a toy for each of pets.Sherman has $22 to spend on pet toys,How much can he spend

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3 years ago

8. Solve the measurement conversion problem. 8 ounces=1cup. Multiply 24x4 then convert to cups

taurus [48]

I believe the answer is D

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3 years ago

Read 2 more answers

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/

VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

$A = \frac{1}{2}bh$ (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

$\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)$

We can find the base by solving equation (1) for b:

$b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm$

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

$2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)$

$\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min$

Therefore, the base is decreasing at 2 cm/min.

I hope it helps you!

7 0

2 years ago