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tamaranim1 [39]

3 years ago

15

Solve the math problem

1 answer:

Nadusha1986 [10]3 years ago

4 0

<u>Answer:</u>

Below!

<u>Explanation:</u>

Exponents are small numbers that defines how many times does the base needs to multiply itself. Two exponents can also be classified in words. 'Squared' defines a number multiplying itself two times. 'Cubed' defines a number multiplying itself three times. If there is a zero as the base's exponent, this means that the result will always be 1. Now, let's solve all the problems together.

2¹ = 2
3⁵ = 3 x 3 x 3 x 3 x 3 = 243
4³ = 4 x 4 x 4 = 64
6⁴ = 6 x 6 x 6 x 6 = 1256
7⁴ = 7 x 7 x 7 x 7 = 2401
1⁶ = 1 x 1 x 1 x 1 x 1 x 1 = 1
8² = 8 x 8 = 64
2³ = 2 x 2 x 2 = 8
4⁴ = 4 x 4 x 4 x 4 = 256
10³ = 10 x 10 x 10 = 1000
12² = 12 x 12 = 144
5⁴ = 5 x 5 x 5 x 5 = 625
6² = 6 x 6 = 36
3⁶ = 3 x 3 x 3 x 3 x 3 x 3 = 729
7³ = 7 x 7 x 7 = 343
2⁴ = 2 x 2 x 2 x 2 = 16
11⁰ = 1
4³ = 4 x 4 x 4 = 64
1¹² = 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 = 1

Hoped this helped!

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andrey2020 [161]

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4vir4ik [10]

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Step-by-step explanation:

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3 years ago

A travelers ground speed is 2 feet per second against the walkway and 8 feet per second with the walkway, what is the travelers

creativ13 [48]

Answer:

The traveller's speed is 5ft/s and the walkway speed is 3ft/s

Step-by-step explanation:

Given

Represent the traveller's speed with T and the walkway's speed with W.

When the traveller walk against the walkway, we have:

$T - W = 2$ ---- i.e. 2ft/s against the walkway

When the traveller walk with the walkway, we have:

$T + W = 8$ ---- i.e. 8ft/s with the walkway

Required

Solve for W and T

$T - W = 2$ --- (i)

$T + W = 8$ --- (ii)

Add (i) and (ii)

$T + T - W + W = 2 + 8$

$T + T = 2 + 8$

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Divide both sides by 2

$\frac{2T}{2} = \frac{10}{2}$

$T = \frac{10}{2}$

$T = 5$

Substitute 5 for T in (ii)

$T + W = 8$

$5 + W = 8$

Make W the subject

$W = 8 - 5$

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maks197457 [2]

Answer:

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Step-by-step explanation:

This is not a math question so there is nothing to put here.

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3 years ago

Find C and D using formula for special right triangles

Anuta_ua [19.1K]

Given:

Right triangles:

To find:

The value of c and value of d

Solution:

<u>In the first right triangle:</u>

θ = 45°

Opposite side to θ = 5

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$$\sin \theta=\frac{\text { Opposite side of } \theta}{\text { Hypotenuse }}$

$$\sin 45^\circ=\frac{5}{c}$

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$$\frac{1}{\sqrt 2}=\frac{5}{c}$

Do cross multiplication, we get

$c=5\sqrt{2}$

<u>In the second right triangle:</u>

θ = 60°

Opposite side to θ = 4

Adjacent side to θ = d

$$\tan \theta=\frac{\text { Opposite side of } \theta}{\text { Adjacent side of } \theta}$

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Do cross multiplication, we get

$$d=\frac{4}{\sqrt{3} }$

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4 years ago