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stiv31 [10]
3 years ago
14

Define respiration in plants:

Chemistry
2 answers:
Mariulka [41]3 years ago
3 0

Answer:

<u>Respiration in plants:</u> The process of respiration in plants involves using the sugars produced during photosynthesis plus oxygen to produce energy for plant growth. In many ways, respiration is the opposite of photosynthesis. ... As with photosynthesis, plants get oxygen from the air through the stomata.

<u>Transpiration in plants: </u>The water eventually is released to the atmosphere as vapour via the plant's stomata — tiny, closeable, pore-like structures on the surfaces of leaves. Overall, this uptake of water at the roots, transport of water through plant tissues, and release of vapour by leaves is known as transpiration.

Sources (jic)

https://www.usgs.gov/special-topic/water-science-school/science/evapotranspiration-and-water-cycle

https://www.pthorticulture.com/en/training-center/basics-of-plant-respiration/

Good luck!!

dimaraw [331]3 years ago
3 0
1. Respiration in plants involves using the sugars produced during photosynthesis plus oxygen to produce energy for plant growth.

2.Transpiration is the process of water movement through a plant and its evaporation from aerial parts.
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Under certain conditions the rate of this reaction is zero order in dinitrogen monoxide with a rate constant of 0.0067·Ms−1: 2N2
choli [55]

Answer:

5.6 seconds

Explanation:

The reaction follows a zero-order in dinitrogen monoxide

Rate = k[N20]^0 = change in concentration/time

[N20]^0 = 1

Time = change in concentration of N2O/k

Initial number of moles of N2O = 300 mmol = 300/1000 = 0.3 mol

Initial concentration = moles/volume = 0.3/4 = 0.075

Number of moles after t seconds = 150 mmol = 150/1000 = 0.15 mol

Concentration after t seconds = 0.15/4 = 0.0375 M

Change in concentration of N2O = 0.075 - 0.0375 = 0.0375 M

k = 0.0067 M/s

Time = 0.0375/0.0067 = 5.6 s

4 0
3 years ago
Calculate the percentage by mass of oxygen in trioxonitrate (v) acid, (HNO3). [ H=1, N=14, O=16]​
Vadim26 [7]

Answer:

Percentage by mass of oxygen = 76.20% (Approx)

Explanation:

Given:

HNO3

H=1, N=14, O=16]

Find:

Percentage by mass of oxygen

Computation:

HNO3

Total mass = 1 + 14 + 3(16)

Total mass = 63

Mass of oxygen = (3)(16) = 48

Percentage by mass of oxygen = [48/63]100

Percentage by mass of oxygen = 76.20% (Approx)

4 0
3 years ago
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insens350 [35]
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3 0
3 years ago
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siniylev [52]

Answer:

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4. 3.46*10^19 molecules x 1 mol molecules/6.02*10^23 molecules = 5.75*10^-5 mol molecules

5. 5.3*10^20 atoms x 1 mol atoms/6.02*10^23 atoms = 8.8 mol atoms

6. 0.11 mol atoms x 6.02*10^23 atoms/1 mol atoms = 6.6*10^22 atoms

I would suggest looking into "dimensional analysis" for help with this type of material. Dimensional analysis will stick with you all throughout chemistry, so picking it up will be extremely beneficial.

7 0
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