Answer:
Use the app photomath
Step-by-step explanation:
Answer:
B, C, D
Step-by-step explanation:
1, 2, 3 are all greater than 0
Answer:
D. 2/3 per year.
Step-by-step explanation:
3 1
3
÷ 5
=
10
3
÷ 5
=
10
3
×
1
5
=
10 × 1
3 × 5
=
10
15
=
10 ÷ 5
15 ÷ 5
=
2
3
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)
</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.
