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trapecia [35]
3 years ago
7

Which of the following sources could not be used to obtain the DNA of a person lost in a mass disaster? used and unwashed clothi

ng or bed sheets food found in the victim's refrigerator sunglasses regularly used by the person a toothbrush used by the person
Chemistry
2 answers:
IgorLugansk [536]3 years ago
4 0
<h3>Question :</h3>

Which of the following sources could not be used to obtain the DNA of a person lost in a mass disaster?

  • used and unwashed clothing or bed sheets
  • food found in the victim's refrigerator
  • sunglasses regularly used by the person
  • a toothbrush used by the person

<h3>Answer :</h3>

food found in the victim's refrigerator could not be used to obtain the DNA of a person lost in a mass disaster.

So, correct answer is 2nd one.

Molodets [167]3 years ago
3 0

Which of the following sources could not be used to obtain the DNA of a person lost in a mass disaster?

used and unwashed clothing or bed sheets

food found in the victim's refrigerator

sunglasses regularly used by the person

a toothbrush used by the person

Answer :

food found in the victim's refrigerator could not be used to obtain the DNA of a person lost in a mass disaster.

So, correct answer is 2nd one.

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A container of a mixture of 4 gases has a total pressure of 35.7 kPa. Gas A has a partial pressure of 7.8kPa. Gas B has a partia
Maurinko [17]

Answer:

partial pressure of gas D Pd = 15.5 kPa

Explanation:

As per the Dalton's law of partial pressure, in a mixture, pressure exerted by each gas when summed gives the total partial pressure exerted by mixture.

P(Total) = P1+P2+P3.....

Given P(Total) = 35.7 kPa

Partial pressure of gas A Pa = 7.8 kPa

Partial pressure of gas B Pb = 3.7 kPa

Partial pressure of gas C Pc =  8.7 kPa

There, Partial pressure of gas D Pd = P(Total) -(Pa+Pb+Pc)

Pd = 35.7-(7.8+3.7+8.7) = 35.7-20.2 kPa = 15.5 kPa

Therefore, partial pressure of gas D Pd = 15.5 kPa

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3 years ago
What are the 3 best solutions to reducing or stopping the effects of climate change?
postnew [5]

Answer:

1. Stop Cutting down Trees

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3. Less use of Fossil Fuels

Explanation:

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4 0
3 years ago
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Give an example of one type of energy conversion (change to another form). Be sure to explain your example.
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Potential to Kinetic Energy. 
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Which of the following do scientists use to form a hypothesis?
Debora [2.8K]

Explanation:

The scientific method involves making observations and asking questions. Scientists form hypotheses based on these observations and then develop controlled experiments to collecting and analyze data. Using this data, they are able to draw conclusions and form questions for new scientific research.

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3 years ago
Brass is a substitutional alloy consisting of a solution of copper and zinc. A particular sample of red brass consisting of 79.0
Bas_tet [7]

<u>Answer:</u> The molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

<u>Explanation:</u>

Solute is the substance which is present in smaller proportion in a mixture and solvent is the substance which is present in larger proportion in a mixture.

We are given:

(m/m) % of Cu = 79 %

This means that 79 g of copper is present in 100 grams of alloy.

(m/m) % of Zn = 21 %

This means that 21 g of zinc is present in 100 grams of alloy.

As, zinc is present in smaller proportion. So, it is solute and copper is the solvent.

  • <u>Calculating molality of zinc:</u>

To calculate molality of the zinc, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

m_{solute} = Given mass of solute (Zinc ) = 21 g

M_{solute} = Molar mass of solute (Zinc) = 65.3 g/mol

W_{solvent} = Mass of solvent (copper) = 79 g

Putting values in above equation, we get:

\text{Molality of Zinc}=\frac{21\times 1000}{65.3\times 79}\\\\\text{Molality of zinc}=4.07m

  • <u>Calculating molarity of zinc:</u>

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 8740kg/m^3=\frac{8740kg\frac{1000g}{1kg}}{1m^3\times \frac{10^6cm^3}{1m^3}}=\frac{8740g}{1000cm^3}=8.740g/cm^3

(Conversion factors used are:  1 kg = 1000 g &  1m^3=10^6cm^3  )

Mass of solution = 100 g

Putting values in above equation, we get:

8.740g/cm^3=\frac{100.0g}{\text{Volume of zinc}}\\\\\text{Volume of zinc}=11.44cm^3

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molar mass of zinc = 65.3 g/mol

Volume of solution = 11.44cm^3=11.44mL     (Conversion factor:  1cm^3=1mL  )

Mass of zinc = 21.0 g

Putting values in above equation, we get:

\text{Molarity of zinc}=\frac{21\times 1000}{65.3\times 11.44}=28.11M

Hence, the molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

4 0
4 years ago
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