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andrezito [222]
3 years ago
8

What is changed when matter undergoes a physical change?

Chemistry
1 answer:
Furkat [3]3 years ago
3 0
I think its the mass that changes but im not sure
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A same of gas in a rigid container is at 25.0Cand 1.00atm. What is the pressure of the sample when heated to 220.0C
Crazy boy [7]

Answer:

1.654 atm.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and V are constant, and have different values of P and T:

<em>(P₁T₂) = (P₂T₁)</em>

<em></em>

  • Knowing that:

P₁ = 1.0 atm, T₁ = 25°C + 273 = 298 K,

P₂ = ??? atm, T₂ = 220°C + 273 = 493 K,

  • Applying in the above equation

<em>(P₁T₂) = (P₂T₁)</em>

<em></em>

<em>∴ P₂ = (P₁T₂)/(T₁) </em>= (1.0 atm)(493 K)/(298 K) = <em>1.654 atm.</em>

7 0
3 years ago
Wine goes bad soon after opening because the ethanol (CH3CH2OH) dissolved in it reacts with oxygen (O2) gas to form water and aq
andrezito [222]

The number of mole of oxygen needed is of 0.080 mole.

To solve this question, we'll begin by writing the balanced equation for the reaction. This is illustrated below:

<h3>CH₃COOH + 2O₂ —> CO₂ + 2H₂O</h3>

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of O₂ needed to produce 0.080 mole of H₂O. This can be obtained as follow:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Therefore,

0.080 mole of O₂ will also react to produce 0.080 mole of H₂O.

Thus, 0.080 mole of oxygen, O₂, is needed for the reaction.

Learn more: brainly.com/question/1563415

7 0
3 years ago
A 35.0 mL sample of 1.00 M KBr and a 60.0 mL sample of 0.600 M KBr are mixed. The solution is then heated to evaporate water unt
Katarina [22]

Answer: The molarity of KBr in the final solution is 1.42M

Explanation:

We can calculate the molarity of the KBr in the final solution by dividing the total number of moles of KBr in the solution by the final volume of the solution.

We will first calculate the number of moles of KBr in the individual sample before mixing together

In the first sample:

Volume (V) = 35.0 mL

Concentration (C) = 1.00M

Number of moles (n) = C × V

n = (35.0mL × 1.00M)

n= 35.0mmol

For the second sample

V = 60.0 mL

C = 0.600 M

n = (60.0 mL × 0.600 M)

n = 36.0mmol

Therefore, we have (35.0 + 36.0)mmol in the final solution

Number of moles of KBr in final solution (n) = 71.0mmol

Now, to get the molarity of the final solution , we will divide the total number of moles of KBr in the solution by the final volume of the solution after evaporation.

Therefore,

Final volume of solution (V) = 50mL

Number of moles of KBr in final solution (n) = 71.0mmol

From

C = n / V

C= 71.0mmol/50mL

C = 1.42M

Therefore, the molarity of KBr in the final solution is 1.42M

5 0
3 years ago
List the types of friction in order from weakest to strongest
e-lub [12.9K]
Static Friction, Sliding Friction, Rolling Friction, and finally Fluid Friction.
5 0
3 years ago
Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e.,
DaniilM [7]

Answer: a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

.

3 0
2 years ago
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