N
a
2
S
O
4
(
a
q
)
+
B
a
(
N
O
3
)
2
(
a
q
)
→
B
a
S
O
4
(
s
)
+
2
N
a
N
O
3
(
a
q
)
Break up the compounds into ions from which they came and cross out the ones that appear on both sides; those are your
spectator ions
.
2
N
a
+
(
a
q
)
+
S
O
2
−
4
(
a
q
)
+
B
a
2
+
(
a
q
)
+
2
N
O
−
3
(
a
q
)
→
B
a
S
O
4
(
s
)
⏐
⏐
↓
+
2
N
a
+
(
a
q
)
+
2
N
O
−
3
(
a
q
)
Barium sulfate
is insoluble so it doesn't ionize in solution
Write net ionic equation
S
O
2
−
4
(
a
q
)
+
B
a
2
+
(
a
q
)
→
B
a
S
O
4
(
s
)
⏐
⏐
↓
Answer:
7628 y
Explanation:
Carbon-14 is radioactive and it follows the first-order kinetics for a radioactive decay. The first-order kinetics may be described by the following integrated rate law:
![ln(\frac{[A]_t}{[A]_o})=-kt](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%29%3D-kt)
Here:
![[A]_t](https://tex.z-dn.net/?f=%5BA%5D_t)
is the mass, moles, molarity or percentage of the material left at some time of interest t;
![[A]_o](https://tex.z-dn.net/?f=%5BA%5D_o)
is the mass, moles, molarity or percentage of the material initially, we know that initially we expect to have 100 % of carbon-14 before it starts to decay;
is the rate constant;
is time.
The equation becomes:
![ln(\frac{[A]_t}{[A]_o})=-\frac{ln(2)}{T_{\frac{1}{2}}}t](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%29%3D-%5Cfrac%7Bln%282%29%7D%7BT_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7Dt)
Given:
![\frac{[A]_t}{[A]_o} = \frac{40.0 %}{100.0 %}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%20%3D%20%5Cfrac%7B40.0%20%25%7D%7B100.0%20%25%7D)
Solve for time:
![t = -\frac{ln(\frac{[A]_t}{[A]_o})\cdot T_{\frac{1}{2}}}{ln(2)}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7Bln%28%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%29%5Ccdot%20T_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7Bln%282%29%7D)
In this case:
There are 3 possible mole ratios
<h3>Further explanation</h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
<em>N₂(g)+3H₂(g)⇒2NH₃</em>
So mol ratio :
N₂:H₂:NH₃=1:3:2
1 mole N₂
3 mol H₂
2 mole NH₃
3 mole H₂
1 mole N₂
2 mole NH₃
<em />
Answer:
Niels Bohr states that the line spectrum of the hydrogen atom by assuming that the electron revolve in circular paths and that the paths have an allowable radii. ...
Explanation:
discuss the origin of the line citing the bohr theory of the atom specify any energy transitions that are applicable
Niels Bohr states that the line spectrum of the hydrogen atom by assuming that the electron revolve in circular orbits and that orbits have an allowable radii. ... an absorption spectrum is produced, dark lines in the same position as the bright lines in the emission spectrum of an element are produced.
Bohr Atomic Model. Bohr Atomic Model : In 1913 Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. ... The atom will be stable in the state with the smallest orbit
Bohr explains to us that electron revolve round the nuclues of an atom and possess energy levels. they can change energy levels
6.54 x 10^5
When trying to figure out a number in a scientific notation, use this notation!
<span>a*10^<span>b
</span></span>
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